Question

If the loop sits in a uniform magnetic field of 3.5~T3.5 T that is oriented in the horizontal +x direction, what is the magnitude of the torque on the wire loop?

Answer 1

Answer:

The magnitude of the torque on the wire loop is 3.68 Nm.

Explanation:

Given that,

Magnetic field = 3.5 T

Suppose, A circular wire loop with a radius of 62.7 cm lies flat in the horizontal x-y plane and contains a current of 852 mA that runs counter-clockwise in the wire loop when viewed from above.

We need to calculate the area

Using formula of area

$A=\pi r^2$

Put the value into the formula

$A=\pi\times(62.7\times10^{-2})^2$

$A=1.235\ m^2$

We need to calculate the magnitude of the torque on the wire loop

Using formula of magnetic field

$\tau=NIAB\sin90$

Put the value into the formula

$\tau=1\times852\times10^{-3}\times1.235\times3.5\times1$

$\tau=3.68\ Nm$

Hence, The magnitude of the torque on the wire loop is 3.68 Nm.