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stiks02 [169]
3 years ago
9

The gravitational force between two objects (mass1 = 10kg, mass2 = 6kg) is measured when the objects are 12 centimeters apart. I

f the distance between them is increased to 36 centimeters, how does the new gravitational attraction compare to the first one that was measured? A. The new gravitational force is 3 times larger than the old one B. The new gravitational force is 9 times larger than the old one C. The new gravitational force is 3 times smaller than the old one D. The new gravitational force is 9 times smaller than the old one
Physics
1 answer:
Yanka [14]3 years ago
8 0
Since the new distance is 3 times the old distance,
the new force is (1/3²) = 1/9th of the old force.

That's kind-of Choice-D, but I really don't like the way choice-D is worded.
"9 times smaller" is really pretty meaningless.  
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Answer:

(a) F_{net} = 4.19 x 10^{-5} N, and its direction is towards m_{2}.

(b) It must be placed inside a hollow shell.

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F = \frac{Gm_{1}m_{2}  }{r^{2} }

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F_{13} = \frac{6.67*10^{-11}*165*60 }{(0.17)^{2} }

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F_{23} = \frac{6.67*10^{-11}*465*60 }{(0.17)^{2} }

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The net force exerted by the two masses on the 60 kg object is 4.19 x 10^{-5}  N.

(ii) /F_{net}/ = /F_{23}/ - /F_{13}/

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(iii) The direction of the net force is to the right i.e towards m_{2}.

(b) For the net force experienced by the 60 kg object to be zero, it must be placed inside a hollow shell.

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