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Komok [63]
3 years ago
9

The combustion in a gasoline engine may be approximated by a constant volume heat addition process. There exists the air-fuel mi

xture in the cylinder before the combustion and the combustion gases after it, and both may be approximated as air, an ideal gas. In a gasoline engine, the cylinder conditions are 0.95 MPa and 425◦C before the combustion and 1700◦C after it. Determine the pressure at the end of the combustion process
Engineering
1 answer:
ddd [48]3 years ago
5 0

Answer:

the pressure at the end of the combustion is 2.68 MPa

Solution:

As per the question:

Initial Pressure, P = 0.95\ MPa

Temperature before combustion, T = 425^{\circ}C = 273 + 425 = 698 K

Temperature after combustion, T' = 1700^{\circ}C = 1973 K

Now,

To calculate the pressure at the end of combustion, P':

By using the Pressure-Temperature relation from Gay- Lussac's law:

\frac{P}{T} = \frac{P'}{T'}

P' = \frac{P}{T}\times T'

P' = \frac{0.95\times 10^{6}}{698}\times 1973 = 2.68\times 10^{6}\ Pa = 2.68\ MPa

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