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faust18 [17]
2 years ago
9

Leland wants to work in a Production career operating heavy machinery. Which type of education or training should Leland seek?

Engineering
2 answers:
Over [174]2 years ago
6 0

Answer:

c

Explanation:

zhenek [66]2 years ago
4 0

Answer:

it is indeed C

Explanation:

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Technician A says that the definition of torque is how far the crankshaft twists in degrees.Technician B says that torque can re
leonid [27]
Technician B is correct because torque is a force of an object.
6 0
10 months ago
Shortly after the introduction of a new​ coin, newspapers published articles claiming the coin is biased. The stories were based
garik1379 [7]

Answer:

(a) 0.12924

(b) Taking into consideration significance level of 0.05 yet the value of p is greater than 0.05, it suggests that the coin is fair hence the coin can be used at the beginning of any sport event.

Explanation:

(a)

n=200 for fair coin getting head, p= 0.5

Expectation = np =200*0.5=100

Variance = np(1 - p) = 100(1-0.5)=100*0.5=50

Standard deviation, s = \sqrt {variance}=\sqrt {50}= 7.071068

Z value for 108, z =\frac {108-100}{7.071068}= 1.131371

P( x ≥108) = P( z >1.13)= 0.12924

(b)

Taking into consideration significance level of 0.05 yet the value of p is greater than 0.05, it suggests that the coin is fair hence the coin can be used at the beginning of any sport event.

3 0
3 years ago
The sum ofall microscopic forms of energy of a system is quantified as flow energy. a)True b) False
Sliva [168]

Answer: b) False

Explanation: Microscopic energy is the the energy that is based on the  molecular level in a particular energy system. Microscopic energy basically comprise with tiny particles like atoms and molecules .The sum of all microscopic form of energy e together make the internal energy .Therefore, the statement given is false because the sum of all the microscopic forms of energy of a system is quantified as internal energy not flow energy.

3 0
3 years ago
A three-point bending test is performed on a glass specimen having a rectangular cross section of height d 5 mm (0.2 in.) and wi
Anon25 [30]

Answer:

The flexural strength of a specimen is = 78.3 M pa

Explanation:

Given data

Height = depth = 5 mm

Width = 10 mm

Length L = 45 mm

Load = 290 N

The flexural strength of a specimen is given by

\sigma = \frac{3 F L}{2 bd^{2} }

\sigma = \frac{3(290)(45)}{2 (10)(5)^{2} }

\sigma = 78.3 M pa

Therefore the flexural strength of a specimen is = 78.3 M pa

4 0
2 years ago
I will Brainlist<br> "Burning and Inch". Describe this measurement.
MAVERICK [17]

Answer:

what measurement

Explanation:

8 0
2 years ago
Read 2 more answers
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