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Sedbober [7]
2 years ago
13

Alguém para conversa

Engineering
1 answer:
allsm [11]2 years ago
6 0

Answer:

do you need points i got 1,031 points i will give you some

Explanation:

hi how old are you i am 16 and a boy

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3 0
2 years ago
A cylindrical specimen of some metal alloy having an elastic modulus of 124 GPa and an original cross-sectional diameter of 4.2
IrinaVladis [17]

Answer:

the maximum length of the specimen before deformation is 0.4366 m

Explanation:

Given the data in the question;

Elastic modulus E = 124 GPa = 124 × 10⁹ Nm⁻²

cross-sectional diameter D = 4.2 mm = 4.2 × 10⁻³ m

tensile load F = 1810 N

maximum allowable elongation Δl = 0.46 mm = 0.46 × 10⁻³ m

Now to calculate the maximum length l for the deformation, we use the following relation;

l = [ Δl × E × π × D² ] / 4F

so we substitute our values into the formula

l = [ (0.46 × 10⁻³) × (124 × 10⁹) × π × (4.2 × 10⁻³)² ] / ( 4 × 1810 )

l = 3161.025289 / 7240

l = 0.4366 m

Therefore, the maximum length of the specimen before deformation is 0.4366 m

5 0
3 years ago
How does sea navigation work?
ahrayia [7]

Answer:

a clock

Explanation:

you use a clock in water

3 0
2 years ago
A(n)<br> is a safety device commonly<br> used with a slotted nut.
liraira [26]

A safety device called a cotter pin. The cotter pin fits through a hole in the bolt or part. This keeps the nut from turning and possibly coming off.

5 0
3 years ago
15 POINTS! Help.
IRISSAK [1]

Answer: it would  overload

Explanation:

4 0
2 years ago
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