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Answer:
a diameter of D₂ = 0.183 inches would be required
Explanation:
appyling pascal's law
P applied to the hydraulic jack = P required to lift the rock
F₁*A₁ = F₂*A₂
since A₁= π*D₁²/4 , A₂= π*D₂²/4
F₁*π*D₁²/4 = F₂* π*D₂²/4
F₁*D₁²=F₂*D₂²
D₂ = D₁ *√(F₁/F₂)
replacing values
D₂ = D₁ *√(F₁/F₂) = 6 in * √(120 lbf/(4000 lbm * 32.174 (lbf/lbm)) = 0.183 inches
Answer:
Table and chart are attached below
Explanation:
Answer:
#include <iostream>
using namespace std;
int main()
{
int inputNumber ;
cout << "Enter an interstate highway number:";
cin >> inputNumber ;
if(inputNumber<=0 || inputNumber >= 1000)
cout << inputNumber << " is not a valid interstate highway number" << endl ;
else{
if(inputNumber > 99){
cout << "I-"<<inputNumber<< " is auxiliary, ";
int temp = inputNumber % 100 ;
cout <<"serving I-"<<temp<<", ";
if(temp%2==0){
cout << "going east/west." << endl;
}
else{
cout << "going north/south." << endl;
}
}
else{
cout << "I-"<<inputNumber<< " is primary, ";
if(inputNumber%2==0){
cout << "going east/west." << endl;
}
else{
cout << "going north/south." << endl;
}
}
}
return 0;
}
Explanation:
- Check if input number is greater than 99, then display that the input number is auxiliary.
-
Check if remainder of input number/2 is equal to 0, then display that going east/west.
