Answer:
a) 23.551 hp
b) 516.89 hp
Explanation:
<u>given:</u>
<u>required:</u>
the power in hp
<u>solution:</u>
.............(1)
by substituting in the equation (1)
=353.27 lbf
..........(2)
by substituting in the equation (2)
= 2769.29 lbf
power is defined by
P=F.V
353.27*36.67
=12954.411 lbf.ft/s
=12954.411*.001818
=23.551 hp
2769.29*102.67
= 284323 lbf.ft/s
= 284323*.001818
= 516.89 hp
1 liter = .264 gallon
1 km = .621 mile
this means that 58.3km/L is equal to 137.13mpg
so
500/137.13 = 3.65 gallons of gas
3.65 x 3.5 = $12.78
Answer:
Yes,If we use river water which is entering at 20⁰ C in the condenser then it is possible to maintain the pressure of 10 KPa in condenser.
Explanation:
Yes,If we use river water which is entering at 20⁰ C in the condenser then it is possible to maintain the pressure of 10 KPa in condenser.
The saturation temperature of steam is 45.81⁰ C at the pressure of 10 KPa which is higher than 20⁰C of river water. So river water at 20⁰C can be used to maintain the condenser pressure to 10 KPa.