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3 years ago

Can someone please check my answers . It's adding and subtracting fractions. Thanks.

Mathematics

2 answers:

Xelga [282]3 years ago

6 0

They are good except 10

MaRussiya [10]3 years ago

4 0

They are good except 10

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Solve for x: <br> (X+5)^1/2 = (5-2x)^1/4

Greeley [361]

Answer:

X = Negative 2 (-2)

7 0

3 years ago

2,12,72,432 what is the formula?

egoroff_w [7]

Answer: The formula is x6

Step-by-step explanation:

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3 years ago

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):

$y = \int {\left(\frac{1}{2}\cdot x^{2}-\frac{3}{2}\cdot x -1 \right)} \, dx$

$y = \frac{1}{2}\int {x^{2}} \, dx - \frac{3}{2}\int {x} \, dx - \int \, dx$

$y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x + C$

$C = 0 - \frac{1}{6}\cdot 0^{3} + \frac{3}{4}\cdot 0^{2} + 0$

$C = 0$

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

5 0

3 years ago

At the city museum can a chicken cross the road?

ipn [44]

Answer:

How is this related to math?

Step-by-step explanation:

4 0

3 years ago

A,B,C,D are points on the circumference of a circle centre o

Marina86 [1]

The points A,B,C,D make up the circumference of the circle

The measure of angle BAD is 65 degrees

<h3>How to determine the measure of angle BAD?</h3>

The measure of angle ODB is given as:

ODB = 25 degrees

Considering the triangle BOD, we have:

ODB + BOD + DBO = 180

Where:

ODB = DBO = 25

So, we have:

25 + BOD + 25 = 180

Solve for BOD

BOD = 130 degrees

The angle at an arc is twice the angle at the circumference.

So, we have:

BOD = 2 * BAD

Substitute 130 for BOD

130 = 2 * BAD

Divide both sides by 2

65 = BAD

Hence, the measure of angle BAD is 65 degrees