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S_A_V [24]
2 years ago
9

A 540 kg satellite moves through deep space with a speed of 27 m/s. A booster rocket on the satellite fires for 1.4 s, giving a

force to the satellite. The speed of the rocket increases to 31 m/s. Calculate the force given by the booster rocket to the satellite. (Assume that the mass of the satellite remains constant.)
A)1543 N
B)2160 N
C)11,957 N
D)3024 N
Physics
2 answers:
prohojiy [21]2 years ago
6 0

Answer: a

Explanation: because the answer is 1.4444444 and that's the closest

Tema [17]2 years ago
5 0
Answer: A. Hope this helped you
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Answer:

3) Ep = 13243.5[J]

4) v = 17.15 [m/s]

Explanation:

3) In order to solve this problem, we must use the principle of energy conservation. That is, the energy will be transformed from potential energy to kinetic energy. We can calculate the potential energy with the mass and height data, as shown below.

m = mass = 90 [kg]

h = elevation = 15 [m]

Potential energy is defined as the product of mass by gravity by height.

E_{p}=m*g*h\\E_{p}=90*9.81*15\\E_{p}=13243.5[J]

This energy will be transformed into kinetic energy.

Ek = 13243.5 [J]

4) The velocity can be determined by defining the kinetic energy, as shown below.

E_{k}=\frac{1}{2} *m*v^{2}  \\v = \sqrt{\frac{2*E_{k} }{m} }\\ v= \sqrt{\frac{2*13243.5 }{90} }\\v=17.15[m/s]

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Incomplete question, check attachment for completed question

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