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S_A_V [24]
3 years ago
9

A 540 kg satellite moves through deep space with a speed of 27 m/s. A booster rocket on the satellite fires for 1.4 s, giving a

force to the satellite. The speed of the rocket increases to 31 m/s. Calculate the force given by the booster rocket to the satellite. (Assume that the mass of the satellite remains constant.)
A)1543 N
B)2160 N
C)11,957 N
D)3024 N
Physics
2 answers:
prohojiy [21]3 years ago
6 0

Answer: a

Explanation: because the answer is 1.4444444 and that's the closest

Tema [17]3 years ago
5 0
Answer: A. Hope this helped you
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Por favor, necesito ayuda urgente 4. vectores perpendiculares de 25 y 40 unidades cada uno. Hallar gráfica y numericamente el ve
Darina [25.2K]

Answer:

4)  R = 47.17 units , 5)  R= 10,29 unidades, 6)   R= 2994,4 km ,    θ = -33,7

Explanation:

Este es un ejercicio de adición de vectores

4) como los vectores son perpendiculares.

Para encontrar la resultante podemos usar el teorema de pitoras

        R =  √ a² + b²

        R = √√ ( 25² + 40²)

        R =  47,17 unidades

5)  Este caso como el angulo es diferente de 90 debemos usar la relación de pitoras completa

        R² =  a² + b² + 2 a b cos θ

donde el angulo es entre los vectores a y b

        R² = 12² + 16² – 2 12 16 cos 40

        R²= 400 – 294,16

       R= 10,29 unidades

6) En este caso los dos desplazamientos son perpendiculares, por lo cual Usamos el teorema de Pitágoras

          R = √ (2400² + 1600²)

          R= 2994,4 km

para el angulo de este desplazamiento usamos trigonometría

           tan θ = y/x

           θ = tan⁻¹ y/x

           θ = tan⁻¹ 1600/(-2400)

           θ = -33,7  

TRASLATE

This is a vector addition exercise

4) as the vectors are perpendicular.

To find the result we can use the Poreor theorem

        R = √ a² + b²

        R = √ (25² + 40²)

        R = 47.17 units

5) This case, as the angle is different from 90, we must use the complete ratio of the pitoras

        R² = a² + b² + 2 a b cos θ

where the angle is between vectors a and b

        R² = 12² + 16² - 2 12 16 cos 40

         R² = 400 - 294.16

       R = 10.29 units

6) In this case the two displacements are perpendicular, which is why we use the Pythagorean theorem

          R = √ (2400² + 1600²)

          R = 2,994.4 km

for the angle of this displacement we use trigonometry

           tan θ = y / x

           θ = tan⁻¹ y / x

           θ = tan⁻¹ 1600 / (- 2400)

           θ = -33.7

3 0
3 years ago
a mass spring system makes 50 complete osillations in 10 seconds. what is the period and frequency of the oscillations
Oxana [17]

Answer: Period = 0.2 seconds; frequency = 5Hz

Explanation:

Number of oscillations = 50

Time required = 10 seconds

Period (T) = ?

Frequency of the oscillations (F) = ?

A) Recall that frequency is the number of oscillations that the mass spring system completes in one second.

i.e Frequency = (Number of oscillations / time taken)

F = 50/10 = 5Hz

B) Period, T is inversely proportional to frequency. i.e Period = 1/Frequency

T = 1/5Hz

T = 0.2 seconds

Thus, the the period and frequency of the oscillations are 0.2 seconds and 5Hz respectively.

5 0
4 years ago
Can you put this in your own words plz.
strojnjashka [21]
Xenon can be used for things like high pressure arc lamps for motion picture projection, in high pressure arc lamps to produce ultraviolet light and photographic flashes. It is also used to help the radiation detection, for example X-ray counters.


hope it helps
6 0
3 years ago
Read 2 more answers
The energy associated with the seperation of two electrical charges is called
Agata [3.3K]
Electrostatic energy

hope this helped!
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3 years ago
Un tanque cilíndrico de Gasolina tiene 3 metros de longitud y 1.2 metros de diametro y la densidad es igual a 680 kg/m3
aniked [119]

Answer:

2310kg

Explanation:

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3 years ago
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