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frez [133]
3 years ago
12

A projectile is launched with an initial velocity of 60.0 m/s at an angle of 30.0° above the horizontal. How far does it travel?

Physics
2 answers:
Bezzdna [24]3 years ago
8 0

Answer:

Explanation: The initial velocity has two component v x  and v y. The initial velocity in direction of y is given.

igomit [66]3 years ago
3 0

Answer:

D

Explanation:

The range is how far the projectile can go;

R = U^2sin2A/g

Where U is the initial velocity

A is the angle of inclination

=60^2sin2(30)/10 = 3600 sin60 / 10

= 311.8m

The exact answer should 312m

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What happens to the work done when a force is doubled and the distance moved remain the same?​
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Answer:

Work done gets doubled.

Explanation:

The work done by a force is given by :

W = Fd

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F is force and d is distance move

If the force is doubled and the distance moved remain the same, it would mean that the work done becomes double of the initial work done.

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What do scientists call water
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Answer:

h20

Explanation:

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Ket [755]

Answer:

1) D

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3 years ago
Vapor pressure is related to the temperature of the liquid. user: in an open system, the vapor pressure is equal to the _____. i
iVinArrow [24]

Answer

-Directly;  outside air pressure

Vapor pressure is directly related to the temperature of the liquid. user: in an open system, the vapor pressure is equal to the outside air pressure.

Explanation;

-As the temperature of a system increases, the average kinetic energy of the molecules increases in both the liquid and gas phases.

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A hollow cylinder with an inner radius of and an outer radius of conducts a 3.0-A current flowing parallel to the axis of the cy
Artemon [7]

Complete Question:

A hollow cylinder with an inner radius of 4.0mm and an outer radius of 30mm conducts a 3.0-A current flowing parallel to the axis of the cylinder. If the current density is uniform throughout the wire, what is the magnitude of the magnetic field at a point 12mm from its center?

Answer:

The magnitude of the magnetic field = 7.24 μT

Explanation:

Inner radius, a = 4.0 mm = 0.004 m

Outer radius, b = 30 mm = 0.03 m

Radius, r = 12 mm = 0.012 m

let h² = b² - a²

h² = 0.03² - 0.004²

h² = 0.000884

Let d² = r² - a²

d² = 0.012² - 0.004²

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μ = 4π * 10⁻⁷

The magnitude of the magnetic field is given by:

B = \frac{\mu I d^{2} }{2\pi r h^{2} } \\B =  \frac{4\pi * 10^{-7}   * 3* 0.000128^{2} }{2\pi *0.012* 0.000884^{2} }

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7 0
3 years ago
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