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2 years ago

A projectile is launched with an initial velocity of 60.0 m/s at an angle of 30.0° above the horizontal. How far does it travel?

Physics

2 answers:

Bezzdna [24]2 years ago

8 0

Answer:

Explanation: The initial velocity has two component v x and v y. The initial velocity in direction of y is given.

igomit [66]2 years ago

3 0

Answer:

Explanation:

The range is how far the projectile can go;

R = U^2sin2A/g

Where U is the initial velocity

A is the angle of inclination

=60^2sin2(30)/10 = 3600 sin60 / 10

= 311.8m

The exact answer should 312m

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When you are rolling it

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3 years ago

A quick USB charger claims its output current is 1.97Amp. We know that the standard USB output voltage is 5V. What is the output

Arte-miy333 [17]

Answer:

Output power of the charger is 9.85 watts.

Explanation:

It is given that,

Output current of the USB charger, I = 1.97 A

The standard USB output voltage, V = 5 V

We need to find the output power of the charger. It can be determined using the following formula as :

P = V × I

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The output power of the charger is 9.85 watts. Hence, this is the required solution.

3 0

2 years ago

A bullet with mass 1.0kg and velocity 180 m/s is brought to rest in 0.02 s by a sandbag.assuming constant acceleration in the sa

kotykmax [81]

Hello
The bullet is moving by uniformly accelerated motion.
The initial velocity is $v_i=180~m/s$ , the final velocity is $v_i=0~m/s$ , and the total time of the motion is $\Delta t=0.02~s$ , so the acceleration is given by
$a= \frac{v_f-v_i}{\Delta t} = -9000~m/s^2$
where the negative sign means that is a deceleration.
Therefore we can calculate the total distance covered by the bullet in its motion using
$S=v_i t + \frac{1}{2}at^2 = 180~m/s \cdot 0.02~s + \frac{1}{2}(-9000~m/s^2)(0.02~s)^2=1.8~m$
So, the bullet penetrates the sandbag 1.8 meters.

5 0

2 years ago

In a cyclic process, a gas performs 123 J of work on its surroundings per cycle. What amount of heat, if any, transfers into or

Margaret [11]

Answer:

123 J transfer into the gas

Explanation:

Here we know that 123 J work is done by the gas on its surrounding

So here gas is doing work against external forces

Now for cyclic process we know that

$\Delta U = 0$