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frez [133]
3 years ago
12

A projectile is launched with an initial velocity of 60.0 m/s at an angle of 30.0° above the horizontal. How far does it travel?

Physics
2 answers:
Bezzdna [24]3 years ago
8 0

Answer:

Explanation: The initial velocity has two component v x  and v y. The initial velocity in direction of y is given.

igomit [66]3 years ago
3 0

Answer:

D

Explanation:

The range is how far the projectile can go;

R = U^2sin2A/g

Where U is the initial velocity

A is the angle of inclination

=60^2sin2(30)/10 = 3600 sin60 / 10

= 311.8m

The exact answer should 312m

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The average speed during any time interval is equal to the total distance of travel divided by the total time. Let d represent t
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Answer:

Average speed = 3.63 m/s

Explanation:

The average speed during any time interval is equal to the total distance travelled divided by the total time.

That is,

Average speed = distance/ time

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Let t1 be the time for which she has the higher speed of 5.15 m/s. Therefore,

5.15 = d/t1.

Make d the subject of formula

d = 5.15t1

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2.80 = d/t2.

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7 0
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The movement of a magnetic pole away from the actual pole
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Answer:

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