A projectile is launched with an initial velocity of 60.0 m/s at an angle of 30.0° above the horizontal. How far does it travel?

Physics

2 answers:

Bezzdna [24]3 years ago

8 0

Answer:

Explanation: The initial velocity has two component v x and v y. The initial velocity in direction of y is given.

igomit [66]3 years ago

3 0

Answer:

Explanation:

The range is how far the projectile can go;

R = U^2sin2A/g

Where U is the initial velocity

A is the angle of inclination

=60^2sin2(30)/10 = 3600 sin60 / 10

= 311.8m

The exact answer should 312m

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