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2 years ago

How do scientists predict the polarity of molecules, the distribution of non-polar and polar molecules?

Chemistry

2 answers:

EastWind [94]2 years ago

8 0

Answer:

Explanation:

Polar molecules interact with other molecules of similar polarity to form solutions. Non-polar molecules do not interact the same way.

andre [41]2 years ago

5 0

Answer:

The scientists predict the polarity of molecules and the distribution of non polar and polar molecules by finding out the net dipole moment of the molecular structure.

Explanation:

The net value of dipole moment is found out with the help of finding the bond angle between the atoms of the given molecule along with the distance between the atoms and the charge on the atoms of the molecule.

This will be applied in the appropriate formula which tells whether the molecule is polar or non polar.

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If you exhale 7.25×10 to the 24th power molecules of CO2. How many moles of CO3 do you exhale?

Assoli18 [71]

None since CO3 does not exist.

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3 years ago

13. A mixture of MgCO3 and MgCO3.3H2O has a mass of 3.883 g. After heating to drive off all the water the mass is 2.927 g. What

rjkz [21]

Answer:

63.05% of MgCO3.3H2O by mass

Explanation:

of MgCO3.3H2O in the mixture?

The difference in masses after heating the mixture = Mass of water. With the mass of water we can find its moles and the moles and mass of MgCO3.3H2O to find the mass percent as follows:

Mass water:

3.883g - 2.927g = 0.956g water

Moles water -18.01g/mol-

0.956g water * (1mol/18.01g) = 0.05308 moles H2O.

Moles MgCO3.3H2O:

0.05308 moles H2O * (1mol MgCO3.3H2O / 3mol H2O) =

0.01769 moles MgCO3.3H2O

Mass MgCO3.3H2O -Molar mass: 138.3597g/mol-

0.01769 moles MgCO3.3H2O * (138.3597g/mol) = 2.448g MgCO3.3H2O

Mass percent:

2.448g MgCO3.3H2O / 3.883g Mixture * 100 =

6 0

2 years ago

Which functional group is found in salicylic acid but not in aspirin?

velikii [3]

Answer: 1. Alcohol 2. Ester

Explanation:

Right on edge.

3 0

3 years ago

Read 2 more answers

PLZZZZZ help ASAP!!!!!!! THANK YOU. :) i need all 3 and thank you again!

Allisa [31]

A.Transform
B.Divergent
C. Convergent

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2 years ago

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For a process Arightwards harpoon over leftwards harpoonB, at 25 °C there is 10% of A at equilibrium while at 75 °C, there is 80

Lostsunrise [7]

This question is describing the following chemical reaction at equilibrium:

$A\rightleftharpoons B$

And provides the relative amounts of both A and B at 25 °C and 75 °C, this means the equilibrium expressions and equilibrium constants can be written as:

$K_1=\frac{90\%}{10\%}=9\\\\K_2=\frac{20\%}{80\%} =0.25$

Thus, by recalling the Van't Hoff's equation, we can write:

$ln(K_2/K_1)=-\frac{\Delta H}{R}(\frac{1}{T_2} -\frac{1}{T_1} )$

Hence, we solve for the enthalpy change as follows:

$\Delta H=\frac{-R*ln(K_2/K_1)}{(\frac{1}{T_2} -\frac{1}{T_1} ) }$

Finally, we plug in the numbers to obtain:

$\Delta H=\frac{-8.314\frac{J}{mol*K} *ln(0.25/9)}{[\frac{1}{(75+273.15)K} -\frac{1}{(25+273.15)K} ] } \\\\\\\Delta H=4,785.1\frac{J}{mol}$

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2 years ago