All categories

3 years ago

6 reasons to believe or disbelieve in Bigfoot. For Science

2 answers:

6 0

Believe: 1. The Gimlin/Patterson film
2. Footprints and other evidences
3. Hair samples
4. Native American legends
5. The Bering Land Bridge
6. Discovery of the Modern Gorilla

Kaylis [27]3 years ago

6 0

Disbelieve:

1. Hair samples coming out to belong to other animals

2. TV channels and You tube videos are fake.

3. Some sighting end up being bears and any animals

4. Their is no real up close seeing.

5. People report a bigfoot sighting in different parts in the u.s. But, if it's in the same places every time it's more believable. Right?

6. If he's real than he needs to eat bears, dears, and fish to survive. Why is their no sighting in rivers and died animals.

You might be interested in

A 2137 kg car moving east at 12.91 m/s collides with a 3264 kg car moving north. The cars stick together and move as a unit afte

IRINA_888 [86]

Answer:

The speed of the 3264 kg car before collision is 6.32 m/s

Explanation:

Let first car, mass m₁, moving east be moving with velocity, v₁ and second car, mass m₂, moving north be moving with velocity, v₂. Let the velocity of the two cars after collision be v₃

In a Collison (whether elastic or inelastic), momentum is always conserved.

Momentum before collision = momentum after collision.

Momentum before collision = m₁v₁ + m₂v₂

v₁ = (12.91î) m/s in vector form, m₁ = 2137 kg

v₂ = ?, v₂ = (v₂j) m/s in vector form, m₂ = 3264 kg

Momentum before collision = (2137)(12.91î) + (3264)(v₂j) = (27590î + 3264v₂j) kgm/s

Momentum after collision = (total mass of the cars after collision) × (velocity of the stuck-together cars after collision)

Total mass of the cars after collision = m₁ + m₂ = 2137 + 3264 = 5401 kg

Velocity after collision, v₃ = 6.38 m/s In the N36.8°E direction, put in vector form,

v₃ = (6.38 cos 36.8°î + 6.38 sin 36.8°j)

v₃ = (5.11î + 3.82j) m/s

Momentum after collision = 5401 (5.11î + 3.82j) = (27590î + 20641.4j) kgm/s

Momentum before collision = momentum after collision.

(27590î + 3264v₂j) = (27590î + 20641.4j)

Comparing components

3264v₂ = 20641.4j

v₂ = 6.32 m/s

Hope this Helps!!!

6 0

4 years ago

This questic concerns a tablet that

Vanyuwa [196]

Answer:

The remaining percentage of drug concentration is about 88.7% 2 years after manufacture.

Explanation:

Recall the formula for the decay of a substance at an initial $N_0$ concentration at manufacture:

$N(t)=N_0\,e^{-k\,\,t}$

where k is the decay rate (in our case 0.06/year), and t is the elapsed time in years. Therefore, after 2 years since manufacture we have:

$N=N_0\,e^{-0.06\,\,(2)}\\N=N_0\,e^{-0.12}\\N/N_0=e^{-0.12}\\N/N_0=0.8869$

This in percent form is 88.7 %. That is, the remaining percentage of drug concentration is about 88.7% 2 years after manufacture.

3 0

3 years ago

A rock at the top of a 20 meter tall hill.The rock has a mass of 10 kg. How much potentail energy does it have?

ch4aika [34]

P.E.=mgh
= 10x10x20
=2000J

6 0

3 years ago

Spiderman, whose mass is 74.0 kg, is dangling on the free end of a 11.0-m-long rope, the other end of which is fixed to a tree l

Anestetic [448]

Answer:

W = -1844.513 J

Explanation:

GIVEN DATA:

mass of spider man is m 74 kg

vertical displacement if spider is 11 m

final displacement = 11 cos 60.6 = - 6.753 m

change in displacement is = -6.753 - (-11) = 4.25 m

gravity force act on spiderman is f = mg = 74 × 9.8 = 725.2 N

work done by gravity is $W = F \delta r cos\theta$

$W = 725.2 \times 4.25 \times cos 180$

where 180 is the angle between spiderman weight and displacement

W = -1844.513 J

7 0

3 years ago

one mole of water is equivalent to 18 grams of water. a glass of water has a mass of 200 g. how many moles of water is in this?

ehidna [41]

1 mole = 18 g
200 g = glass of water
200 ÷ 18 = 11.1
11.1 moles of water in 200 g (glass of water)

3 0

3 years ago