The picture below shows a person exploring an underwater cave in Florida.

Physics

1 answer:

lubasha [3.4K]3 years ago

6 0

Underwater caves in Florida are primarily formed due to the abundance of limestone layers just situated below the ground, forming the "Floridan Aquifer." Layers of these limestones are believed to be thousands of meters thick. When rainwater is being seeped into the ground, it softens the calcite present in limestones due to its acidic nature until it is dissolved. This leads to the formation of cavities and tunnels which eventually becomes an interconnected network of passages over time. As water continues flowing through these passages, which builds up from the bottom of these cavernous empty spaces, underwater caves are then formed. Therefore, the first choice is the answer.

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As a child walks, for a brief moment his entire weight is placed on one heel, which can be approximated as a small circle. Calcu

Brut [27]

The correct answer is option b, 63.6 kPa

Given,

The diameter of the heel, d=7 cm=0.07 m

The mass of the child, m=25 kg

The pressure is given by the ratio of the force to the area through which the force is applied.

The force applied on the floor by the child is equal to its weight.

Thus the pressure applied on the floor by the child is given by,

$\begin{gathered} P=\frac{F}{A} \\ =\frac{mg}{\pi(\frac{d}{2})^2} \end{gathered}$

Where A is the area of the cross-section of the heel.

On substituting the known values,

$\begin{gathered} P=\frac{25\times9.8}{\pi(\frac{0.07}{2})^2} \\ =63.6\times10^3\text{ Pa} \\ =63.6\text{ kPa} \end{gathered}$

Thus the pressure applied on the floor by the heel is 63.6 kPa

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11 months ago

A simple ideal Brayton cycle uses argon as the working fluid. At the beginning of the compression, P1 = 15 psia and T1 = 70°F, t

Shtirlitz [24]

B I thing hope this helps

7 0

3 years ago

One end of a thin rod is attached to a pivot, about which it can rotate without friction. Air resistance is absent. The rod has

Scrat [10]

Answer:

5.24 m/s

Explanation:

So for the rod to be able to rise upward to the straight up position, the kinetic energy caused by linear speed v0 must be just enough to convert into the potential energy.

Since the rod is uniform in mass, we can treat the body as 1 point, at its center of mass, or geometric center, aka 0.35 / 2 = 0.175 m from the pivot.

For the rod to swing from bottom to top, the center must have moved a distance of h = 0.175 * 2 = 0.35 m, vertically speaking.

Since we neglect friction and air resistance, according to the law of energy conservation then:

$E_k = E_p$

$mv^2/2 = mgh$

Where v is the speed at the center of mass, g = 9.81 m/s2 is the gravitational acceleration, and m is the mass. We can divide both sides by m

$v^2 = 2gh = 2*9.81*0.35 = 6.867$

$v = \sqrt{6.867} = 2.62 m/s$

As this is only the speed at the center of mass, the speed at the bottom end would be different, to calculate this, we need to find the common angular speed:

$\omega = v / r = 2.62 / 0.175 = 14.97 rad/s$