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Stolb23 [73]
3 years ago
11

If a nearsighted person has a far point dfdfd_f that is 3.50 mm from the eye, what is the focal length f1f1f_1 of the contact le

nses that the person would need to see an object at infinity clearly?
Physics
1 answer:
Ira Lisetskai [31]3 years ago
4 0

Answer:

person must have to use the concave lens of focal length 3.5 m

Explanation:

If the person can see upto distance of 3.5 m from eye

then in order to see the object at large distance we need to use

d_o = infinite

d_i = -3.5 m

so by lens formula we have

\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}

\frac{1}{-3.5} + 0 = \frac{1}{f}

so we have

f = -3.5 m

so person must have to use the concave lens of focal length 3.5 m

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Repeat the experiment to make sure it gives the same results.

Hope i helped ; )
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Two point charges lie on the x axis. A charge of + 2.30 pC is at the origin, and a charge of − 4.50 pC is at x=−11.0cm.
Radda [10]

r₁ = distance of point A from charge q₁ = 0.13 m

r₂ = distance of point A from charge q₂ = 0.24 m

r₃ = distance of point A from charge q₃ = 0.13 m

Electric field by charge q₁ at A is given as

E₁ = k q₁ /r₁² = (9 x 10⁹) (2.30 x 10⁻¹²)/(0.13)² = 1.225 N/C     towards right

Electric field by charge q₂ at A is given as

E₂ = k q₂ /r₂² = (9 x 10⁹) (4.50 x 10⁻¹²)/(0.24)² = 0.703 N/C    towards left

Since the electric field in left direction is smaller, hence the electric field by the third charge must be in left direction

Electric field at A will be zero when

E₁ = E₂ + E₃

1.225 = 0.703 + E₃

E₃ = 0.522 N/C

Electric field by charge "q₃" is given as

E₃ = k q₃ /r₃²

0.522 = (9 x 10⁹) q₃/(0.13)²

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4 0
4 years ago
Doctor prescribed drug which is 500mg for patient change this unit into gram
ololo11 [35]

Answer:

.5 grams

Explanation:

1 gram is equal to 1000 milligrams (mg)

6 0
4 years ago
A ball is thrown horizontally from the top of a building 100m high. The ball strikes the ground at a point 120 m horizontally aw
astraxan [27]

26.54 m/s  is the magnitude of its velocity just before it strikes the ground

h=100m,v=20m/s,g=9.8m/s

time it takes to reach the ground,

[t=\sqrt2h/g],[=\sqrt2*100/9.8=4.51s]

x= 120m

t= 4.52

v= x/t

v= 120/4.52

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The "speed at which an object changes its location" can be expressed using a vector number called velocity. Consider a person who moves swiftly while taking two steps forward and two steps back while remaining in one location. Velocity is a vector quantity. Therefore, velocity is cognizant of direction. The direction must be taken into account when determining an object's velocity. A speed of 55 mph is not enough information. The direction must be used to appropriately depict the item's velocity. Simply said, the direction of the velocity vector indicates the direction of motion of an object.

To know more about  velocity visit : brainly.com/question/16379705

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5 0
1 year ago
a circular cylinder and isused to maintain a water depth of 4 m. That is, when the water depth exceeds 4 m, thegate opens slight
stiv31 [10]

Answer:

  W / A = 39200 kg / m²

Explanation:

For this problem let's use the equilibrium equation of / newton

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We replace

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On the other side the cylinder cover has a pressure

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We match the two equations

       P A = ρ A h g

        P = ρ g h

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The weight of the water column is

       W  = 1000 9.8 4 A

       W / A = 39200 kg / m²

3 0
4 years ago
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