A meter stick with a mass of 0.155 kg is pivoted about one end so it can rotate without friction about a horizontal axis. The me
ter stick is held in a horizontal position and released. As it swings through the vertical, calculate:
a. change in gravitational potential energy that has occurred;
b. the angular speed of the stick;
c. the linear speed of the end of the stick opposite the axis.
d. Compare the answer in part (c) to the speed of a particle that has fallen 1.00m, starting from rest.
a. change in gravitational potential energy that has occurred;
b. the angular speed of the stick;
c. the linear speed of the end of the stick opposite the axis.
d. Compare the answer in part (c) to the speed of a particle that has fallen 1.00m, starting from rest.
1 answer:
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Answer:
755.37 N
Explanation:
We are given that
Mass of venus=
Radius=m
Mass of human=
We know that the gravitational force between two bodies
Where G=Gravitational constant=
Using the formula
The magnitude of the gravitational force exerted by Venus on the human=
The magnitude of the gravitational force exerted by Venus on the human=F=