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NeX [460]
3 years ago
5

A meter stick with a mass of 0.155 kg is pivoted about one end so it can rotate without friction about a horizontal axis. The me

ter stick is held in a horizontal position and released. As it swings through the vertical, calculate:
a. change in gravitational potential energy that has occurred;
b. the angular speed of the stick;
c. the linear speed of the end of the stick opposite the axis.
d. Compare the answer in part (c) to the speed of a particle that has fallen 1.00m, starting from rest.

Physics
1 answer:
brilliants [131]3 years ago
4 0

Answer: a) P.E = - 0.76J

b) W = 2.7 rad/s

c) V = 2.7m/a

d) V = 4.43 m/s

Explanation: Please find the attached files for the solution

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A proton having an initial velvocity of 20.0i Mm/s enters a uniform magnetic field of magnitude 0.300 T with a direction perpend
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The time interval for which the proton remains in the field is -

Δt = $\frac{\pi R}{40}.

We have a proton entering a uniform magnetic field which is in a direction perpendicular to the proton's velocity.

We have to determine time interval during which the proton is in the field.

<h3>What is the magnitude of force on the charged particle moving in a uniform magnetic field?</h3>

The magnitude of force on the charged particle moving in a uniform magnetic field is given by -

F = qvB sinθ



According to the question, we have -

Entering Velocity (v) = 20 i  m/s

Magnetic field intensity (B) = 0.3 T

Leaving velocity (u) = - 20 j  m/s

Now -

The entering and leaving velocity vectors have 90 degrees difference between them. Therefore, only a quarter of distance of the complete circular path of radius 'R' is traced by the proton. Therefore -

d = $\frac{2\pi r}{4} = $\frac{\pi R}{2}

Since, the radius of circular path is not given, we will assume it R.

Therefore, time for which proton remained in the field is -

t = $\frac{\pi R}{2v} = \frac{\pi R}{40}

Hence, the time interval for which the proton remains in the field is -

Δt = $\frac{\pi R}{40}

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6 0
2 years ago
Need help ASAP please Thanks
Karo-lina-s [1.5K]
Answer: D
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When forces acting on an object
Ksju [112]

Answer:

it will not change

Explanation:

if the forces are of equal force then there would be no movement because one force was not stronger to move it

6 0
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How can you describe the path of the projectile motion?
tresset_1 [31]

Answer:

Projectile motion is a form of motion where an object moves in a bilaterally symmetrical+ parabolic path.

Explanation:

5 0
3 years ago
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When a fluid flows over an object, the "friction drag": __________.A.is the drag due to the shear stress only. B. depends only o
astra-53 [7]

Answer:

D. is greater for turbulent flow than for laminar flow

Explanation:

what is friction drag?

  • friction drag is a phenomenon experienced when a body moves through a fluid. A practical example can be seen in the mild warmth we experience rubbing the palm's of one's hand together only in this case we are dealing with a solid body and a fluid (e.g air, water). friction drag is directly proportional to the area of the surface in contact with the fluid and increases as velocity increases. We see a practical example of this when the rate at which one rubs the palms together is fast but we use the word turbulent when we are dealing with fluids. Turbulent flow creates more friction drag than laminar flow( Flow between a smooth body and fluid) due to its greater interaction with the surface of the body
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