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NeX [460]
2 years ago
5

A meter stick with a mass of 0.155 kg is pivoted about one end so it can rotate without friction about a horizontal axis. The me

ter stick is held in a horizontal position and released. As it swings through the vertical, calculate:
a. change in gravitational potential energy that has occurred;
b. the angular speed of the stick;
c. the linear speed of the end of the stick opposite the axis.
d. Compare the answer in part (c) to the speed of a particle that has fallen 1.00m, starting from rest.

Physics
1 answer:
brilliants [131]2 years ago
4 0

Answer: a) P.E = - 0.76J

b) W = 2.7 rad/s

c) V = 2.7m/a

d) V = 4.43 m/s

Explanation: Please find the attached files for the solution

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Answer:

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If a jump lasts for 1.8 seconds this means that from the moment when the person leaves the ground till the person touches the ground again it takes 1.8 seconds. So, maximum height reached will be at half the time of the jump i.e., 0.9 seconds.

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s=ut+\frac{1}{2}at^2\\\Rightarrow s=0t+\frac{1}{2}9.81\times 0.9^2\\\Rightarrow s=3.97305\ m

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読めませんか?

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