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nalin [4]
3 years ago
10

[OU.01] The diagram below shows two waves, Wave 1 and Wave 2, traveling in the same medium.[OU.01] The diagram below shows two w

aves, Wave 1 and Wave 2, traveling in the same medium. Based on the diagram, which of these properties of Wave 2 is half of the same property of Wave 1?  A:frequency  B:amplitude C:wavelength D:velocity

Physics
2 answers:
In-s [12.5K]3 years ago
8 0
Amplitude Because the distance from the line of equilibrium to a Crest or trough is the waves amplitude
Fantom [35]3 years ago
5 0

The answer is not amplitude. I will update with the correct answer when I figure it out; however, amplitude is incorrect.

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Which of the following types of models could be used to represent a cell?
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A 75.5 kg diver drops from a diving board 10.0 m above the waters surface. Find the divers speed just before he strikes the wate
jenyasd209 [6]

Answer:

<em>v=14 m/s</em>

Explanation:

<u>Mechanical Energy </u>

The kinetic energy of a body (K) is the capacity of doing work due to its speed. It can be expressed as

\displaystyle K=\frac{mv^2}{2}

The potential energy (U) is the capacity of doing work due to its height respect to a certain reference level.

U=mgh

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\displaystyle E_m=\frac{mv^2}{2}+mgh

The principle of conservation of mechanical energy states it must remain the same if no external force is acting on it. The diver drops from the diving board, which means its initial speed is zero (and so its initial kinetic energy). Thus, the mechanical energy at the jumping time is

\displaystyle E_m=mgh=(75)(10)(9.8)=7350\ J

When the diver is about to get into the water, his height reaches zero and the speed is at maximum. All the potential energy became kinetic energy, so

\displaystyle \frac{mv^2}{2}=7350\ J

Rearranging

\displaystyle v^2=\frac{2(7350)}{75}=196

v=\sqrt{196}=14\ m/s

The final speed of the diver is

\boxed{v=14\ m/s}

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3 years ago
When using the lens equation, a negative value as the solution for di indicates that the image is
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Answer:

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Diverging Lenses - Ray Diagrams

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The Mathematics of Lenses

Ray diagrams can be used to determine the image location, size, orientation and type of image formed of objects when placed at a given location in front of a lens. The use of these diagrams was demonstrated earlier in Lesson 5 for both converging and diverging lenses. Ray diagrams provide useful information about object-image relationships, yet fail to provide the information in a quantitative form. While a ray diagram may help one determine the approximate location and size of the image, it will not provide numerical information about image distance and image size. To obtain this type of numerical information, it is necessary to use the Lens Equation and the Magnification Equation. The lens equation expresses the quantitative relationship between the object distance (do), the image distance (di), and the focal length (f)

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3 years ago
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