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Gnom [1K]
3 years ago
13

When using the lens equation, a negative value as the solution for di indicates that the image is

Physics
1 answer:
nirvana33 [79]3 years ago
3 0

Answer:

The Anatomy of a Lens

Refraction by Lenses

Image Formation Revisited

Converging Lenses - Ray Diagrams

Converging Lenses - Object-Image Relations

Diverging Lenses - Ray Diagrams

Diverging Lenses - Object-Image Relations

The Mathematics of Lenses

Ray diagrams can be used to determine the image location, size, orientation and type of image formed of objects when placed at a given location in front of a lens. The use of these diagrams was demonstrated earlier in Lesson 5 for both converging and diverging lenses. Ray diagrams provide useful information about object-image relationships, yet fail to provide the information in a quantitative form. While a ray diagram may help one determine the approximate location and size of the image, it will not provide numerical information about image distance and image size. To obtain this type of numerical information, it is necessary to use the Lens Equation and the Magnification Equation. The lens equation expresses the quantitative relationship between the object distance (do), the image distance (di), and the focal length (f)

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A 3.5 x 10-6 C charge is located 0.28 m from a 2.8 x 10-6 C charge. What is the magnitude of the force being exerted on the smal
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The electrostatic force between two charges is given by Coulomb's law:
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r is the separation between the two charges

By substituting the data of the problem into the equation, we can find the magnitude of the force between the two charges:
F=(8.99 \cdot 10^{9} Nm^2C^{-2} ) \frac{(3.5 \cdot 10^{-6} N/C)(2.8 \cdot 10^{-6}N/C)}{(0.28m)^2}=1.2 N
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ASAP! State the direction of<br> the oscillation of a<br> longitudinal wave??<br> Worth 40 P! ASAP!
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In a longitudinal wave the particle displacement is parallel to the direction of wave propagation. ... The particles do not move down the tube with the wave; they simply oscillate back and forth about their individual equilibrium positions.Answer:

Explanation:

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E<br> 3.6 What force is needed to give a mass of<br> 20 kg an acceleration of 5 m/s??
luda_lava [24]

Explanation:

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Three masses are located in the x- y plane as follows: a mass of 6 kg is at (0 m, 0 m), a mass of 4 kg is at (3 m, 0 m), and a m
enot [183]

Answer:

The center of mass of three mass in the x-y plane is located at (1,0.5).                  

Explanation:

It is given that, a mass of 6 kg is at (0,0), a mass of 4 kg is at (3,0), and a mass of 2 kg is at (0,3). We need to find the center of mass of the system. Center of mass in x direction  is :

C_x=\dfrac{6\times 0+4\times 3+2\times 0}{6+4+2}\\\\C_x=1

The center of mass in y direction is :

C_y=\dfrac{6\times 0+4\times 0+2\times 3}{6+4+2}\\\\C_y=0.5

So, the center of mass of three mass in the x-y plane is located at (1,0.5).

3 0
3 years ago
A truck covered 2/7 of a journey at an average speed of 40
sertanlavr [38]

Answer:

The amount of time for the whole journey is 8 hours.

Explanation:

A truck covered 2/7 of a journey at an average speed of 40  mph. Representing 1 the total of the trip traveled, then the rest of the distance traveled is calculated as: 1-\frac{2}{7} =\frac{5}{7}

So if the truck covered the remaining 200 miles at \frac{2}{7}, this means that \frac{5}{7} of the trip represents the 200 miles. So, to calculate the total distance traveled by the truck, you apply the following rule of three: if \frac{5}{7} of the route represents 200 miles, the integer 1 (which represents the total of the route), how many miles are they?

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miles= 280

So the total distance traveled is 280 miles. Since speed is the relationship between the space traveled by an object and the time used for it (speed=\frac{distance}{time}), then if the average of the entire trip was 35 mph and the distance traveled 280 miles, the time is calculated as:

time=\frac{distance}{speed}=\frac{280 miles}{35 mph}

time= 8 h

<u><em> The amount of time for the whole journey is 8 hours.</em></u>

<u><em /></u>

6 0
3 years ago
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