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inysia [295]
3 years ago
15

What is on the x-axis of a speed graph

Physics
1 answer:
Digiron [165]3 years ago
6 0

Answer: distance

Explanation:

Speed equals distance over time

Meaning time is on y axis and distance is on x axis

Time will always, Always be on y axis

So in any formula time will be on y axis and your other unit will be on x axis in this case s=d/t d being distance

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A small oil droplet is sprayed between the plates of a parallel plate capacitor. The droplet has a net charge equal to that of 3
masha68 [24]

Answer:

…..

Explanation:

give brainiest

6 0
3 years ago
A 55kg cannonball is fired out of a 1500kg cannon with an acceleration of 18m/s/s. With what acceleration did the cannon recoil?
dedylja [7]
F=ma so (55kg)(18m/s^2)=990N so to find a of cannon we know force of cannon ball = 990N therefore 990N/1500kg=.66m/s^2 

Hope this helps you understand the concept of Newtons Second Law of F=ma!!!

8 0
3 years ago
If the direction of a magnetic field around a vertical electrical wire is counter clockwise, what direction is the electrical cu
jasenka [17]

Direction of the current:

From the bottom of the wire to the top

Explanation:

The magnetic field produced by a current-carrying wire forms concentric circles around the wire; its magnitude is given by

B=\frac{\mu_0 I}{2\pi r}

whrere

\mu_0 is the vacuum permeability

I is the current in the wire

r is the distance from the wire

The direction of the magnetic field produced by a current-carrying wire can be found by using the right-hand rule:

- The thumb of the right hand is placed in the same direction as the current

- The other fingers, wrapped around the thumb, give the direction of the magnetic field

In this case, the wire is vertical and the magnetic field is counter clockwise (looking from the top), therefore we need to put the thumb from the bottom to the top in order to get the same direction for the field: therefore, the direction of the current is

From the bottom of the wire to the top

Learn more about magnetic fields:

brainly.com/question/3874443

brainly.com/question/4240735

#LearnwithBrainly

8 0
3 years ago
(a) When the terminals of a 100-V battery are connected to two parallel plates 1 cm apart, what is the electrical field in the r
DaniilM [7]

Answer:

The electrical field in the region between the plates is 10,000 V/m.

Explanation:

Given;

potential difference between the two parallel plates, V = 100 V

distance between the two parallel plates, d = 1 cm = 0.01 m

The electrical field in the region between the plates is given as;

E = V / d

where;

E is the electrical field in the region between the plates

E = (100) / (0.01)

E = 10,000 V/m

Therefore, the electrical field in the region between the plates is 10,000 V/m.

3 0
3 years ago
Consider a spring that does not obey Hooke's law very faithfully. One end of the spring is fixed. To keep the spring stretched o
ohaa [14]

Answer:

The work done will be 0.115 J.

Explanation:

Given that,

k=100\ N/m

b=700\ N/m^2

c=12000\ N/m^3

A force along the x-axis with x-component,

F(x)=kx-bx^2+cx^3

Suppose, How much work must be done to stretch this spring by 0.050 m from its unstretched length?

We need to calculate the work done

Using formula of work done

W(x)=\int{F(x)dx}

Put the value into the formula

W(x)=\int{(kx-bx^2+cx^3)dx}

W(x)=\dfrac{kx^2}{2}-\dfrac{bx^3}{3}+\dfrac{cx^4}{4}

Put the value of k,b,c and x

W(0.050)=\dfrac{100\times(0.050)^2}{2}-\dfrac{700\times(0.050)^3}{3}+\dfrac{12000\times(0.050)^4}{4}

W(0.050)=0.115\ J

Hence, The work done will be 0.115 J.

7 0
3 years ago
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