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Natalka [10]
3 years ago
5

A 2.5 kg cat is resting on top of a bookshelf that is 3 meters high. What is the cats gravitational potential energy relative to

the floor if the acceleration due to gravity is 9.8 m/s ^2
Physics
1 answer:
erma4kov [3.2K]3 years ago
4 0

Answer:

The answer to your question is Ep = 73.6 Joules

Explanation:

Data

mass = 2.5 kg

height = 3 m

gravity = 9,81 m/s²

Potential energy = ?

Potential energy is the energy stored in an object due to its position, the highest the object be, the highest the potential energy.

Formula

Pe = mgh

Substitution

Ep = (2.5)(9.81)(3)

Simplification and result

Ep = 73.6 Joules

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Virty [35]

The velocity, 50 m/s, has two components - vertical and horizontal velocities.

The vertical component = 50 sin 30 = 25 m/s

The horizontal component = 50 cos 30 = 43.3 m/s

(a)  Let t be the time taken for the vertical component to reach its peak from initial velocity = 25 m/s to its final velocity = 0.

     Using the linear motion equation v = u - gt

     0 = 25 - 10t

     t = 2.5 s

    Time taken to go up and down = 5 s

    Time to hit the ground = 5 s

(b) Horizontal distance dealt x = 43.3 * 5 = 216.5 m

This is not the correct answer, but explains the problem thoroughly.

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Answer:

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Describe a scenario where a car's speed could stay the same, but the acceleration changes.
k0ka [10]

Answer:

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3 years ago
If a ball is thrown vertically upward from the roof of 32 foot building with a velocity of 64 ft/sec, its height after t seconds
stepan [7]

Answer:

a) s_{max} = 96\,ft, b) v(4.449\,s) = -78.368\,\frac{ft}{s}

Explanation:

a) The maximum height is obtained with the help of the First and Second Derivative Tests:

First Derivative

v(t) = 64 - 32\cdot t

64 - 32\cdot t = 0

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Second Derivative

a(t) = -32 (absolute maximum)

The maximum height reached by the ball is:

s (2\,s) = 32 + 64\cdot (2\,s) - 16\cdot (2\,s)^{2}

s_{max} = 96\,ft

b) The time required by the ball to hit the ground is:

32+64\cdot t - 16\cdot t^{2} = 0

-16\cdot (t^{2}-4\cdot t - 2) = 0

t^{2}-4\cdot t - 2 = 0

(t -4.449)\cdot (t+0.449)\approx 0

Just one root offers a solution that is physically reasonable:

t = 4.449\,s

The velocity of the ball when it hits the ground is:

v(4.449\,s) = 64 - 32\cdot (4.449\,s)

v(4.449\,s) = -78.368\,\frac{ft}{s}

6 0
3 years ago
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