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Aliun [14]
3 years ago
11

what is the average acceleration of a car if a car rest from 0m/s and reaches a final velocity is 50m/s in 10m/s

Physics
1 answer:
GuDViN [60]3 years ago
6 0

Answer:

Assuming that you meant the final velocity of 50 m/s was reached in 10 s, the answer would be 5 m/s^2.

Explanation:

V_{f} = V_{i} + at

So we update that with the values that we have.

50 = 0 +a(10)

then simplify that using algebra to solve for a and we get 5 m/s^2

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A skier with a potential energy of 137,200 J waits on top of a ski jump that is 200 m high. What is the mass of the skier?
defon
PE = mgh
137200 = mg x 200
686 = mg
686/9.81 = m
m = 69.9286.... (idk how many decimals / sig. figs. you need)
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3 years ago
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A wire along the z axis carries a current of 6.4 A in the z direction Find the magnitude and direction of the force exerted on a
almond37 [142]

Answer:

The magnetic force will be 0.256 N in +y direction.                                          

Explanation:

It is given that, a wire along the z axis carries a current of 6.4 A in the z direction. Length of the wire is 8 cm. It is placed in uniform magnetic field with magnitude 0.50 T in the x direction.

The magnetic force in terms of length of wire is given by :

F=I(L\times B)\\\\F=ILB\\\\F=6.4\times 0.08\times 0.5\\\\F=0.256\ N

For direction,

F=I k(L\times Bi)\\\\F=Fj

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7 0
3 years ago
The speed of sound in water is 1,492 m/s. A sonar signal is sent straight down from a ship at a point just below the water's sur
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Answer:

5595 m

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The wave travels down   (the depth) and the back up (the depth again)

  this distance is     2 d

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2 years ago
What demonstrates the flow of energy and materials through
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3 0
1 year ago
The half-wave rectifier circuit of vs(t) = 170 sin(377t) V and a load resistance R = 15Ω. Determine: a. The average load current
irina1246 [14]

Answer:

a  average load current = 11.33 A

b rms load current = 8.02A

c true power =962.64 W

d apparent power =962.64 W

e. power factor cosθ =1

Explanation:

Vs (t) = 170 sin(377t) v

Vm =170v

Vrms = 170/√2 =120.23 v

Im = Vm/R = 170/15 = 11.33 A

Irms = Im/ √2 = 11.33/√2 =8.02A

Resistors are electronic components that consume energy

the power in a resistor is given by  P =IVcosθ ; in a resistor cosθ =1

P =IV

The electrical power consumed by a resistance, (R) is called the true or real power

and is obtained by multiplying the rms voltage with the rms current.

P= Vrms × Irms

120.03×8.02

P= 962.64 W ; true power

apparent power = Vrms × Irms

=120.03×8.02

= 962.64W ; apparent power

power factor cosθ = true power/ apparent power

cosθ = 962.64/962.64

cosθ = 1

For the purely resistive circuit, the power factor is 1 , because the reactive power is equal to zero (0).

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