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Vitek1552 [10]
2 years ago
6

How many moles of hydrogen are in 3. 06 × 10⁻³ g of glycine , c₂h₅no₂?.

Chemistry
1 answer:
Gala2k [10]2 years ago
8 0

Answer:

n = 6.06 x 10^{-4} mol

Explanation:

n =?

m = 3.06 x 10-³ g

M (H5) = 5 x 1.01 (Since we only want hydrogen)

Atomic mass of C = 12.01

Atomic mass of H is 1,01, etc.

Having this data, we can use the Molar mass formula and change it so we can know the quantity of matter (n) in moles, and we just replace it.

M = \frac{m}{n} ⇔ n = \frac{m}{M} ⇔ n = \frac{3.06 x 10^{-3} }{5,05} ⇔ n = 6.06 x 10^{-4} mol

Note: The numbers I've used may be different from yours, by a small difference. I don't know if it's the case, but hope it helped.

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                             C₆H₁₂O₆    ⇒    2C₂H₅OH(l) +2CO₂(g)

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Solve for n

                             n = \frac{PV}{RT}

Substitution

                             n = \frac{(1)(2.25)}{(0.082)(295)}

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                         x = (0.046 x 180) / 1

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Given that G for the reaction below is –957.9 kJ, what is Gf of H2O? 4NH3(g) + 5O2(g) =4NO(g) + 6H2O(g)
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Answer:

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