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loris [4]
3 years ago
15

Which statement is true about a base when it reacts with another substance?

Chemistry
2 answers:
Maurinko [17]3 years ago
7 0

Answer:

A. It receives a hydrogen ion.

Explanation:

The Bronsted lowry theory of acids and bases solves this problem. The theory states that;

Any compound that can transfer a proton to any other compound is an acid, and the compound that accepts the proton is a base. A proton is a nuclear particle with a unit positive electrical charge; it is represented by the symbol H+ because it constitutes the nucleus of a hydrogen atom.

So among the options, the option that says a base receives a hydrogen ion is the right answer which is option A.

Take the following reaction for example:

HCl  + NH₃    ⇌  NH₄⁺  +  Cl⁻

Hydrochloric acid (HCl) is the Brønsted-Lowry acid because it donates a hydrogen ion. Ammonia (NH3) is the Brønsted-Lowry base because it accepts the hydrogen ion.

Nostrana [21]3 years ago
4 0

Answer:   a. It receives a hydrogen ion.

Explanation:  Base is a species which is capable of donating its negative quantity and accepting the positive one.

For example, ammonia is considered as a base because it is capable of donating its lone pairs of electrons and can accept an proton as well.

Here, out of the given options, Hydrogen H^{+} is a proton which is acting as a positive species and hydroxide ion OH^{-} is a negative species.

Thus, option (A) is the correct answer as it will receive a hydrogen ion from another base making itself a conjugate acid.

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Answer:

B

Explanation:

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4 years ago
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An aqueous solution containing 17.5 g of an unknown molecular (nonelectrolyte) compound in 100.0 g of water has a freezing point
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Answer:

molar mass = 180.833 g/mol

Explanation:

  • mass sln = mass solute + mass solvent

∴  solute: unknown molecular (nonelectrolyte)

∴ solvent: water

∴ mass solute = 17.5 g

∴ mass solvent =  100.0 g = 0.1 Kg

⇒ mass sln = 117.5 g

freezing point:

  • ΔTc = - Kc×m

∴ ΔTc = -1.8 °C

∴ Kc H2O = 1.86 °C.Kg/mol

∴ m: molality (mol solute/Kg solvent)

⇒ m = ( - 1.8 °C)/( - 1.86 °C.Kg/mol)

⇒ m = 0.9677 mol solute/Kg solvent

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∴ mol solute = ( m )×(Kg solvent)

⇒ mol solute = ( 0.9677 mol/Kg) × ( 0.100 Kg H2O )

⇒ mol solute = 0.09677 mol

⇒ Mw solute = ( 17.5 g ) / ( 0.09677 mol )

⇒ Mw solute = 180.833 g/mol

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Natural gas and petroleum are mostly alkanes t/f
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Answer:

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Explanation:

Hope this helps

8 0
3 years ago
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