Answer: 0.023 liters
Explanation:
Given that,
Original volume of gas (V1) = 25mL
[convert 25mL to liters
If 1000ml = 1L
25ml = 25/1000 = 0.025L]
Original temperature of gas (T1) = 22°C
[Convert 22°C to Kelvin by adding 273
22°C + 273 = 295K]
New volume of gas (V2) = ?
New temperature of gas (T2) = 0°C
[Convert 0°C to Kelvin by adding 273
0°C + 273 = 273K]
Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law
V1/T1 = V2/T2
0.025L/295K = V2/273K
To get the value of V2, cross multiply
0.025L x 273K = 295K x V2
6.825L•K = 295K•V2
Divide both sides by 295K
6.825L•K/295K = 295K•V2/295K
0.023 L = V2
Thus, the new volume of the gas will be 0.023 litres
Answer:
K = 2.7x10⁻⁵ at 25ºC
Explanation:
A way to write Arrhenius equation is:
ln K = - Ea/R × (1/T) + lnA
If you graph ln K as Y and 1/T as X (Absolute temperature in K), the equation you will obtain is:
Y = -13815X +35.817
R² = 0.9927
(Taking the last k point as 0.0386) (ln 0.0386), <em>0.1386 has no sense</em>)
Your slope is -13815
-13815K = - Ea/R
-13815K×8.314J/molK = 114858J/mol = Ea
And your intercept =
lnA = 35.817
A = 3.59x10¹⁵
Now, you want to know rate constant at 25ºC = 298.15K. Replacing in the equation (Where Y is ln (activation energy) and X is 1/T):
Y = -13815X +35.817
Y = -13815(1/298.15K) +35.817
Y = -10.5187
lnK = -10.5187
<h3>K = 2.7x10⁻⁵ at 25ºC</h3>
The AC unit uses a refrigerant generally a chemical called freon to cool the air in a house. The unit evaporates freon and uses the result of this evaporation cycle to circulate cool air. ... Freon is a gas. The AC unit compresses this cool gas, causing it to become very hot.
Answer:
B.111
Explanation:
Atomic mass = number of protons(or atomic number) + number of neutrons
186 = 75 + number of neutrons
number of neutrons = 186 -75 = 111
