It would be 65 miles per hour
The solution has a concentration 20 mgr in each mL of the final solution.
To solve this problem, we need to know about concentration. The concentration formula can be defined as how much the mass per unit volume is. It can be written as
M = m/V
where M is concentration, m is mass of solute, V is the total volume of solution.
From the text we know that :
m = 10g
vsolvent = 45mL
vsolute = 5 mL
find the total volume (V)
V = vsolvent + vsolute
V = 45 + 5
V = 50mL
Then, find the concentration
M = m/V
M = 10gr / 50 mL
M = 1000 mgr / 50mL
M = 20 mgr / mL
Hence, the solution has a concentration 20 mgr in each mL of the final solution.
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75% is the chance that they will have detached earlobes
6,50g of ZnSO4 is 0,04 moles
Mass
of ZnSO4 :
m=6,50g
<span>Molar
mass of ZnSO<span>4 : </span></span>
M=M(Zn)+M(S)+4*M(O)
M=65,38
g/mol+32,06 g/mol+4*15,99 g/mol
M=161,40 g/mol
Molarity of ZnSO4 :
n=m/M
n=6,50g/161,40g/mol
n=0,04 mol
Answer:Heat released in kilo Joule per gram of benzene when reacted with oxygen is 0.628 kJ/g.
Explanation:
The standard enthalpy of formation of benzene is 49.04 kJ/mol. Same amount of energy will be released on combustion of 1 mol of benzene.

Mass of 1 mol of benzene = 78 g
1 mole of benzene on combustion gives = 49.04 kJ
78 g of benzene on combustion gives = 49.04 kJ
1 g of benzene on combustion will give = 
Heat released in kilo Joule per gram of benzene when reacted with oxygen is 0.628 kJ/g.