All categories

4 years ago

What is the answer ?

Mathematics

1 answer:

notka56 [123]4 years ago

4 0

Answer:

A) 2

Step-by-step explanation:

In a box-and-whisker plot, the left "whisker" is the bottom 25%, the line between the two "boxes" is to 50%, and the right "whisker" is the top 25%.

In class 2, the 90 point mark is where the line between the boxes are, which means that 50% of the class earned 90% or less. That is 13/2 = 6.5 people (this is impossible but it will work out)

In class 1, the 80 point mark is also where 50% is. So, half of the students, 17/2 = 8.5 people, have 80 points or less.

8.5 - 6.5 = 2 people.

You might be interested in

Evaluate x=-3, y=4, z=-5 Answers suggested below -17 41 23 -40 -58 -16

tatiyna

Answer:

2. -16

6. 23

7. -40

8. -17

9. 41

10. -58

6 0

3 years ago

Robert wants to build a square sandbox that has an area of 25 feet.How long will each side be

telo118 [61]

Each side will be 5 feet long

3 0

3 years ago

If f'(x) and g'(x) exist and

dem82 [27]

not letting me add answer

Refer to the attachment

7 0

2 years ago

What are two factors that add up to the coefficient -13

Gala2k [10]

Answer:

1, 13

-1, -13

here are 2 coefficient factors that multipy to get 13

brain list please?

3 0

3 years ago

Read 2 more answers

A company is interviewing potential employees. Suppose that each candidate is either qualified, or unqualified with given probab

stira [4]

Answer:

$P(C=1|T=1)=q(\sum_{i=15}^{20}\binom{20}{i} p^i(1-p)^{20-i})( \sum_{i=15}^{20}\binom{20}{i}[qp^i(1-p)^{20-i} + (1-q)p^{20-i}(1-p)^i])^{-1}$

Step-by-step explanation:

Hi!

Lets define:

C = 1 if candidate is qualified

C = 0 if candidate is not qualified

A = 1 correct answer

A = 0 wrong answer

T = 1 test passed

T = 0 test failed

We know that:

$P(C=1)=q\\P(A=1 | C=1) = p\\P(A=0 | C=0) = p$

The test consist of 20 questions. The answers are indpendent, then the number of correct answers X has a binomial distribution (conditional on the candidate qualification):

$P(X=x | C=1)=f_1(x)=\binom{20}{x}p^x(1-p)^{20-x}\\P(X=x | C=0)=f_0(x)=\binom{20}{x}(1-p)^xp^{20-x}$

The probability of at least 15 (P(T=1))correct answers is:

$P(X\geq 15|C=1)=\sum_{i=15}^{20}f_1(i)\\P(X\geq 15|C=0)=\sum_{i=15}^{20}f_0(i)\\$

We need to calculate the conditional probabiliy P(C=1 |T=1). We use Bayes theorem:

$P(C=1|T=1)=\frac{P(T=1|C=1)P(C=1)}{P(T=1)}\\P(T=1) = qP(T=1|C=1) + (1-q)P(T=1|C=0)$

$P(T=1)=q\sum_{i=15}^{20}f_1(i) + (1-q)\sum_{i=15}^{20}f_0(i)\\P(T=1)=\sum_{i=15}^{20}\binom{20}{i}[qp^i(1-p)^{20-i} + (1-q)p^{20-i}(1-p)^i)]$

$P(C=1|T=1)=q(\sum_{i=15}^{20}\binom{20}{i} p^i(1-p)^{20-i})( \sum_{i=15}^{20}\binom{20}{i}[qp^i(1-p)^{20-i} + (1-q)p^{20-i}(1-p)^i])^{-1}$

5 0

3 years ago