Answer:
Me too
Step-by-step explanation:
STEP
1
:
1
Simplify —
x
Equation at the end of step
1
:
1 1
— - —
9 x
STEP
2
:
1
Simplify —
9
Equation at the end of step
2
:
1 1
— - —
9 x
STEP
1
:
1
Simplify ——
x2
Equation at the end of step
1
:
1 1 1 1
(—-—) ÷ (——-——)
9 x 81 x2
STEP
2
:
1
Simplify ——
81
Equation at the end of step
2
:
1 1 1 1
(— - —) ÷ (—— - ——)
9 x 81 x2
(9x)/(x+9)-:(x-9)/(9x)
Answer:
True
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Here (h, k) = (- 4, - 9), thus
y = a(x + 4)² - 9
To find a substitute the coordinates of the zero (- 7, 0) into the equation.
0 = a(- 7 + 4)² - 9, that is
0 = 9a - 9 ( add 9 to both sides )
9a = 9 ( divide both sides by 9 )
a = 1, thus
y = (x + 4)² - 9 ← expand factor using FOIL
y = x² + 8x + 16 - 9
y = x² + 8x + 7
Answer:
(x+4)(x-3) or A
Step-by-step explanation:
I'm going to assume that you meant to write x² and not x2
which means we have
x²+x-12
and we need to factor this
to do this we need two numbers that add up to 1 (b) but mulitply to -12 (a*c)
our two numbers are
4, -3
Which means the answer is
(x+4)(x-3)
YOU WILL NOT FAIL, YOU SHALL PASS
Answer: w^6/9
Step-by-step explanation:
first, i evaluated the powers.
3^-2 x 1 x 1/w^-6
then, i calculated those products.
3^-2/w^-6
then, i just expressed it with a positive exponent.
w^6/3^2
finally, i evaluated that.
w^6/9