The maximum number of roots to a polynomial of order n is n roots. Take the example of a quadratic (order 2) which can intersect the x-axis a maximum of 2 times, and similarly a cubic (order 3) 3 times maximum.
Hence for 8 intersections, minimum order = 8
A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 20 is about 4.472. Thus, the square root of 20 is not an integer, and therefore 20 is not a square number.
Answer:
150
Step-by-step explanation:
To solve the problem, put 5 instead of x, so 5*3
and put 10 instead of y, so 10*1
when combined,
(5*3) * (10*1)
= 15 * 10
= 150
Hope this helps!!
Let me know if I'm wrong...
Answer:
20 degrees
Step-by-step explanation:
we can consider 33 to be the radius of a circle.
31 would then be the cos of the angle in that circle.
the regular cos function is defined for the standard circle with radius 1. so, that would be multiplied by 33 for this circle here.
31 = cos(?) × 33
cos(?) = 31/33 = 0.9393...
? = 20.05 ≈ 20 degrees
X should equal 12.5
You have to split the isosceles acute triangle in the middle of the polygon down the middle, and find what the now right isosceles tringle is. Since we already know that there's a 50 degress and a 90 degress there all you have to do is add those two numbers together and subtract from 180. Thena after you've done that you just need to multiply 40 by 2 and bata bing, bata boom you have 80 degress as your top, you already have a 50 and the last one has to be 50. Divide 50 by 4 and you get 12.5
50+90=140
180-140=40
40 * 2 = 80
80 + 50 + x = 180
x= 50
4*x= 50
x=12.5
