Question

A gear pump has a 4.25in outside diameter, a 3.25in inside diameter, and a 2in width. If the actual pump flow rate is 1800rpm and rated pressure is 29gpm, what is the volumetric efficiency?

Answer 1

Answer:

volumetric efficeincy = 0.315%

Explanation:

Given data:

outside diameter = 4.25 inch

inside diameter = 3.25 inch

flow rate V = 1800 rpm

actual flow rate Qa = 29gpm = 6699 inch3/min

volume of pump can be determine by using below formula

$VOLUME = \frac{\pi}{4}*(D_{0}^{2}-D_{1}^{2})L$

              $=\frac{\pi}{4}*(4.25^{2}-3.25^{2})2$

$VOLUME = 11.78 inc^{3}$

theoretical flow rate is given as Qt

$Q_{T} = V.N$

         = 11.78*1800

         =$21204 inch ^{3}/ min$

$volumetric efficeincy = \frac{Q_{A}}{Q_{T}}$

                                   $=\frac{6699}{21204}$

volumetric efficeincy = 0.315%