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Brilliant_brown [7]
3 years ago
8

Starting the vehicle's engine and listening to its operation can

Engineering
1 answer:
miskamm [114]3 years ago
3 0
I pretty sure it’s true because you can start your car and it sounds different that probably means something is wrong
You might be interested in
Select the correct answer.
andrezito [222]

Answer:

it is A. balance

Explanation:

6 0
3 years ago
Estimate horizontal and vertical tail sizes fo r a twin-turboprop regional transport with wing area of 40 m2, aspect ratio of 10
svetlana [45]

Answer: 0.2m sqr

Explanation:

A well behaved aircraft basically have a value of volume in horizontal and vertical area.

Volume in horizontal area (Vh) = 0.6

Volume in vertical area (Vv) = 0.05

Having known this, consider the relationship to find the vertical and horizontal tail sizes.

Vertical tail area (Sv)

Horizontal tail area (Sh)

Vh= (Sh × I) / S

Where,

I = moment

S= wing area

Sh= Horizontal tail area

Vh= Volume in horizontal area

0.6= Sh × 10/40

24= 10Sh

Sh= 24/10

Sh= 2.4 msqr

Horizontal tail area= 2.4m sqr

From the information above, we can calculate the vertical tail area.

Vertical tail area is calculated thus below:

Vv= (Sv× I) / S

Where

Vv= Volume in vertical area

Sv= Vertical tail area

I= Moment

S= Wing area

Therefore

Sv= (Vv × S) /I

Sv= (0.05×40)/10

Sv= 0.2msqr

In conclusion, the vertical tail size is 0.2msqr

7 0
3 years ago
Read 2 more answers
An alloy to be used for a spring application must have a modulus resilience of at least 0.79 x 106 J/m3 (0.79 x 106 Pa). What mu
xxTIMURxx [149]

Answer:

4.13 MPa

Explanation:

Given

Modulus of elasticity = E = 102 GPa

E = 102 * 10^9

Modulus resilience U = 0.79 * 106Pa

Modulus of Resilience U = y²/2E --- Make y the subject of formula

y² = 2EU

y = √(2EU)

y = √(2 * 102 * 10^9 * 0.79 * 106)

y = √1.708296E13

y = 4133153.759540044

y = 4.13E6

y = 4.13MPa

3 0
3 years ago
A small probe P is gently forced against the circular surface with a vertical force F as shown . Determine the n- and t-componen
Rina8888 [55]

This question is incomplete, its missing an image which will be uploaded along this Answer.

Answer:

the normal component of force F_n is F((√(r²-s²)) / r)

the tangential component of force F_t is F(s/r)

Explanation:

Given the data in the image;

from the free body diagram, we write the expression for ∅

sin∅ = s/r

cos∅ = (√(r²-s²)) / r

now expression for normal component of force is;

F_n = Fcos∅

we substitute

F_n = F((√(r²-s²)) / r)

Therefore, the normal component of force F_n is F((√(r²-s²)) / r)

Also for force F_t

F_t = Fsin∅

we substitute

F_t = F(s/r)

Therefore, the tangential component of force F_t is F(s/r)

6 0
3 years ago
The typical Canadian worker is able to produce 100 board feet (a unit of measure) of lumber or 1000 light bulbs per year. The wo
faltersainse [42]

Answer:

Explanation:

In the Canadian country, it is possible that the country is able to produce either 100 units of lumber or 1000 lightbulbs. Then, 100 lumber is equal to 1000 bulbs in the home, and hence, one lumber is equivalent to 10 bulbs. Therefore, the opportunity cost of lumber in the home is ten bulbs.

Thus, the country's production possibilities frontier PPF is a linear combination of 100 lumber and 1000 bulbs. The graphical diagram of the production possibilities frontier PPF can be seen in the image below.

6 0
3 years ago
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