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Explanation:
Answer:
Algorith does not work.
Explanation:
One of the ways to obtain the Dekker Algorithm is through a change in the declaration, that is, a declaration that can be executed at the exact moment it leaves the critical section. This way it is possible that the statement,
turn = 1-i / * P0 sets turn to 1 and P1 sets turn 0 * /
It can be changed to,
turn = (turn +1) \% n / * n = number or processes * /
The result will allow to define if it works or not, that is, if it is greater than 2 the algorithm will not be able to work.
Given this consideration we can say that,
<em>- The dead lock does not occur, because the mutual is imposed (if a resource unit has been assigned to a process, then no other process can access that resource).</em>
<em>- There is the possibility of starving if the shift is established in a non-contentious process.</em>
Directly it can be concluded that there is a possibility of starvation so the algorithm could not work, despite the fact that mutual exclusion guarantees that a dead block does not occur.
Answer:
//Convert any decimal number to binary number
//Program is written in C++ Programming Language
// Comments are used for explanatory purpose
// Program starts here
#include <iostream>
using namespace std;
// Main Method declared here
int main()
{
int x;
cout<<"Enter any integer number: ";
cin>>x;
DecBin(x);
return 0;
}
// Here a function named DecBin is declared along with an integer variable, x
void DecBin(int x)
{
// Declare an array to store the resulting binary digits
int bindigit[32];
// counter for binary array
int kount = 0;
while (x > 0) {
// Store the remainder of each division in the declared array
bindigit[kount] = x % 2;
x = x / 2;
kount++;
}
// Loop to print the binary digits in reverse order
for (int j = i - 1; j >= 0; j--)
{
cout << bindigit[j];
}
}
// End of Program
Answer and Explanation:
The main objective that the torsion test serves is the determination of the material behavior or the behavior of the test sample when subjected to torsional stresses or forces due to the application of moments that results in shear stress along the axis.
Plasticity is the property of elastic material and tension or shear stresses leads to plasticity in a material where these links are the weakest, that gives torsion test a major advantage over the tension test.
Torsion tests are performed on materials to deduct properties like the shear modulus of elasticity, the torsional strength, and the MOR, i.e., Modulus of Rupture.
This test can be used to obtain larger strain values of strain without any complexity as that in tension test.
This test provides a curve of shear-stress-shear strain which is more significant in determining the plasticity as compared to the curve of stress-strain in tension test.
Maximum torque for a given value of maximum stress will be 2 times higher in torsion as that of tension.
In torsion, for plastic flow, the threshold value of shear stress is achieved before the threshold value of normal stress for fracture whereas in tension the critical value of normal stress is achieved sooner than the critical shear for plastic flow.
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