Compare a series circuit powered by six 1.5-volt batteries to a series circuit powered by a single 9-volt battery. Make sure the
re are equal numbers of light bulbs in each circuit and that the batteries are all in the same orientation.
1 answer:
Answer:
Both series circuits provide a total voltage of 9 volts to the two bulbs connected in series and the voltage will be equally divided among two bulbs and they will have same brightness. Therefore, both circuits will have same characteristics.
Explanation:
We are asked to compare two series circuits having equal number of light bulbs.
1st circuit is powered by 6 batteries each having a voltage of 1.5V
2nd circuit is powered by a single battery having a voltage of 9V.
The six batteries in the 1st circuit can be connected together in series or in parallel.
When the batteries are connected in series (positive terminal of one battery connected to negative terminal of another battery) their voltage gets added which means
Voltage of pack = number of batteries*voltage of each battery
Voltage of pack = 6*1.5
Voltage of pack = 9 volts
But the current remains same in the series connection since there is only path for the current to flow.
On the other hand, when the batteries are connected in parallel, the voltage remains same but the current increases.
Circuit 1:
In this circuit, we have 6 batteries each of 1.5 volts connected in series to provide a voltage of 9 volts.
We have connected 2 bulbs in this series circuit.
The voltage will be equally divided between two bulbs if both bulbs are identical in construction.
So there will be 4.5 volts across each bulb and both bulbs will have same brightness.
Circuit 2:
In this circuit, we have 1 battery which provide a voltage of 9 volts.
We have connected 2 bulbs in this series circuit just like in circuit 1.
The voltage will be equally divided between two bulbs if both bulbs are identical in construction.
So there will be 4.5 volts across each bulb and both bulbs will have same brightness.
Conclusion:
Both series circuits provide a total voltage of 9 volts to the two bulbs connected in series and the voltage will be equally divided among two bulbs and they will have same brightness. Therefore, both circuits will have same characteristics.
You might be interested in
Answer:
Explanation:
Given that:
Superheated vapor enters the turbine at 10 MPa, 480°C,
From the tables of superheated steam tables; the following values are obtained
Also; from the system, the isentropic line is 1-2 in which s_2 is in wet state
From the values obtained;
Therefore;
6.52846 = 0.51624+7.82x
6.52846 - 0.51624 = 7.82 x
6.01222 = 7.82 x
x = 6.01222/7.82
x = 0.7688
The enthalpy for this process at state (s_2) can be determined as follows:
The actual enthalpy at s_2 by using the isentropic efficiency of the turbine can determined by using the expression:
kJ/kg
The work pump is calculated by applying the formula:
However;
From the process;
The actual enthalpy at s_4 by using the isentropic efficiency of the turbine can determined by using the expression: