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3 years ago

What is the period if the clock frequency is 3.5 GHz?

Engineering

1 answer:

grin007 [14]3 years ago

7 0

Answer:

Period = 0.2857 nanoseconds

Explanation:

We are told that frequency = 3.5 GHz

This is simply 3.5 × 10^(9) Hz

Now, from wave equations, Period is given by the formula;

Period = 1/frequency

Thus;

Period = 1/(3.5 × 10^(9))

Period = 0.2857 × 10^(-9) seconds

From conversions, we can simplify the answer.

1 second = 10^(-9) nanoseconds

Thus, 0.2857 × 10^(-9) seconds = 0.2857 × 10^(-9) × 10^(-9) nanoseconds = 0.2857 nanoseconds

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11. Wet-cell batteries are commonly referred to as lead-acid batteries. A) O True B) O False

Alja [10]

Is true i think bye ansía

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3 years ago

Stone has been used as a building material since ancient times because of its compressive strength, which is the __________.

Doss [256]

Complete Question:

Stone has been used as a building material since ancient times because of its compressive strength, which is the?

Group of answer choices

A. ability to support pressure without breaking.

B. ability to press down and become solidly fixed in the ground.

C. relative weight of a block of stone to its size.

D. force a block exerts on the blocks around it.

Answer:

A. ability to support pressure without breaking.

Explanation:

Stone has been used as a building material since ancient times because of its compressive strength, which is the ability to support pressure without breaking.

Compressive strength can be defined as the ability of a structural element or particular material to withstand an applied, which is aimed at reducing the size of the structural element.

Simply stated, it is the ability of a structural element or material to withstand an applied load without deflections, fracture or having any crack.

In this context, a stone possesses the ability to resist or withstand compression loads.

Some examples of other materials or structural elements having good compressive strength are steel, bones, concrete etc. The standard unit of measurement of the compressive strength of a material is Mega Pascal (MPa) or pound-force per square inch (psi) in the United States of America.

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4 years ago

Supón que tienes que calcular el centro de gravedad de una pieza

Anton [14]

Answer:huh?

Explanation:

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4 years ago

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Lapatulllka [165]

Answer:

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4 0

3 years ago

Read 2 more answers

The mechanical properties of a metal may be improved by incorporating fine particles of its oxide. Given that the moduli of elas

andriy [413]

Answer:

Uper Bound = 175.5 GPa, Lower Bound = 85.26 GPa

Explanation:

Rule of mixtures equations:

For a two-phase composite, modulus of elasticity upper-bound expression is,

E(c)(u) = E(m) x V(m) + E(p) x V(p)

Here, E(m) is the modulus of elasticity of matrix, E(p) is the modulus of elasticity of patriciate phase, E(c) is the modulus of elasticity of composite, V(m) is the volume fraction of matrix and V(p) is the volume fraction of composite.

For a two-phase composite, modulus of elasticity lower-bound expression is,

E(c)(l) = E(m) x E(p)/V(m) x E(p)+V(p) x E(m)

Consider the expression of rule of mixtures for upper-bound and calculate the modulus of elasticity upper-bound.

E(c)(u) = E(m) x V(m) + E(p) x V(p), (1)

Calculate the volume fraction of matrix.

V(m) + V(p) = 1

Substitute 0.35 for V(p).

V(m) + 0.35 = 1

V(m) = 0.65

From equation (1);

Substitute 60 GPa for E(m), 390GPa for E(p), 0.65 for V(m) and 0.35 for V(p).

E(c)(u )= E(m) x V(m) + E(p) x V(p)

E(c)(u) = (60 × 0.65) + (390 × 0.35)

E(c)(u) = 175.5 GPa

The modulus of elasticity upper-bound is 175.5GPa.

The modulus of elasticity of upper-bound can be calculated using the rule of mixtures expression. Since the sum of volume fraction of matrix and volume fraction of composite is equal to one V(m) + V(p) = 1. Substitute the value of volume fraction of matrix as 0.69 and obtain the volume fraction of matrix.

Consider the expression of rule of mixtures for lower-bound and calculate the modulus of elasticity upper-bound.

E(c)(l) = (E(m) x E(p))/ (V(m) x E(p) + V(p) x E(m))

Substitute 60 GPa for E(m), 390GPa for E(p), 0.65 for V(m) and 0.35 for V(p).

E(c)(l) = 60 × 390/(0.65 × 390) +(0.35 × 60)

E(c)(l) = 23400/274.5

E(c)(l) = 85.26 GPa

The modulus of elasticity lower-bound is 85.26 GPa.

8 0

4 years ago