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kiruha [24]
3 years ago
8

Tech A says that thrust angle refers to the direction the front wheels are pointing. Tech B says that scrub radius refers to the

vertical centerline of the tire in relation to an imaginary line through the steering knuckle pivots. Who is correct?
Engineering
1 answer:
kenny6666 [7]3 years ago
4 0

Both of the technicians are correct.

<u>Explanation:</u>

The thrust angle is defined as the angle formed by the imaginary line drawn perpendicular to the rear axis center line. It is used in alignment of the four wheels.

It is also used to determine the direction the front wheels are pointing. While the scrub radius is the intersecting point of the vertical center line of front tires with the imaginary line drawn from the steering knuckles.

Thus both the technicians are saying correct. The thrust angle and scrub radius are used to determine the alignment of wheels, if there is any misalignment in wheels then it needs to make it correct to prevent accidents.

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Radio Frequency IDentification (RFID) tags and readers are a category of low-end wireless devices that people may not recognize
Fittoniya [83]

Answer:

See explaination.

Explanation:

Radio Frequency Identification (RFID) tags and readers uses the electromagnetic waves to identify and track the attached objects.

A tag is attached to the object which is to be identified or tracked, and reader is used to read the response and send the acknowledgement. Therefore, RFID tags and readers are used in many industries, passports, transportations and pet identification etc.

i.

RFID technology is used in smartcards, implants for pets, passports and library books to identify and track the persons, objects and pets etc.

Hence, we can say that option (i) is true.

ii.

Electronic Product Code (EPC) is a small code stored in the RFID tag. The code stored in the memory is 96 bits which are used to identify the organization which manages the data, unique number to identify the product and a number to identify the particular tag and etc.

EPC is a unique identification number, it can read and be written by the RFID reader. It is used in supply chains instead of a bar code even though expansive.

Hence, option (ii) is true.

iii.

Tags are used to identify and track the objects. It doesn’t belong to base stations and access points as a Wi-Fi networks.

Therefore, option (iii) is false.

iv.

The EPC Generation 2 RFID tag is used to improve the security by enabling the authentication features. It is not the similar way of data transmission in the other wireless situations.

Therefore, option (iv) is false.

Finally, the options (i) and (ii) are TRUE, while (iii) and (iv) are FALSE.

8 0
3 years ago
Consider a reliable data transfer protocol that uses only negative acknowledgements. Suppose the sender sends data only infreque
kenny6666 [7]

Answer:

Refer to explaination

Explanation:

A NAK only protocol is not preferable to a protocol that uses ACKs especially when the sender sends data frequently.

This is because NAK only protocol will be able to detect that a packet has been lost already when the receiver receives the subsequent packet. Also, as the sender only sends data infrequently, NAK only protocol takes a longer time to realize that a packet has been lost.

On the other hand, NAK only protocol is preferred to a protocol that uses ACKs, when the sender sends data out frequently, here the data loss rate is low.

7 0
3 years ago
Anne works for NASA. She was responsible for developing an aerodynamic design of a space shuttle. What type of engineer is she?
sesenic [268]

Answer:

Anne is an aeronautical engineer.

Explanation:

7 0
3 years ago
An automobile having a mass of 884 kg initially moves along a level highway at 68 km/h relative to the highway. It then climbs a
IRISSAK [1]

Answer:

ΔK.E. = - 142.72 kJ

Explanation:

mass = 884 kg

initial velocity = 68 km/h = 68 \times \frac {5}{18} = 18.89 m/s

final velocity = 0 m/s

height = 69 m

change in kinetic energy :

ΔK.E. = \dfrac{1}{2}m(v_f^2-v_i^2)

ΔK.E. =\dfrac{1}{2}\times 884 \times (0^2-18.89^2)

ΔK.E. =-142,716.05 J

ΔK.E. =-142.72 kJ

hence change in  kinetic energy of the automobile is  -142.72 kJ

6 0
3 years ago
True or False: Conditions, like the number of times repeated, are used to end a [Repeat] block.
Alja [10]

Answer:

True. needa type in 20 more letters

Explanation:

ye.

4 0
3 years ago
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