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dybincka [34]
3 years ago
15

If an aqueous solution has a ph of 5.57 what is the concentration of hydroxide ion ([oh-]) in the solution?

Chemistry
1 answer:
irga5000 [103]3 years ago
8 0
PH=5.57
pH+pOH=14
5.57 + pOH=14
pOH = 14-5.57= 8.43

pOH = - log  [OH⁻]
-pOH=  log  [OH⁻]


[OH^{-}] = 10^{-pOH}= 10^{-8.43}= 3.72*10^{-9}

 [OH^{-}]= 3.72*10^{-9}
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Answer:

Explanation:

Moles of sodium

=

130

⋅

g

22.99

⋅

g

⋅

m

o

l

−

1

=

5.65

⋅

m

o

l

.

Now you have the stoichiometric equation:

2

N

a

(

s

)

+

2

H

2

O

(

l

)

→

2

N

a

O

H

(

a

q

)

+

H

2

(

g

)

↑

⏐

If there are

5.65

⋅

m

o

l

of metal, clearly

5.65

⋅

m

o

l

2

dihydrogen gas are evolved......, i.e.

2.83

⋅

m

o

l

H

2

. Typically, in a question like this, you would also be asked to calculate the volume the gas occupies under standard conditions, and the

p

H

of the resultant solution (would it be high, low, neutral?).

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