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3 years ago

What is the tool used for measuring volume?

Chemistry

1 answer:

RoseWind [281]3 years ago

4 0

Answer:

Liquid volume is usually measured using either a graduated cylinder or a buret. As the name implies, a graduated cylinder is a cylindrical glass or plastic tube sealed at one end, with a calibrated scale etched (or marked) on the outside wall.

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Can all matter be categorized as elements?

AfilCa [17]

Answer:

heyy, I hope this helps! In short words yes.

5 0

3 years ago

If the temperature of a gas decreases at constant volume which of the following would occur

Zepler [3.9K]

Answer:

I need the things after "which of the following would occur".

Explanation:

If you were to maintain a constant volume while decreasing pressure, the temperature would also have to decrease. This is Boyle's law.

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3 years ago

What are the different acid bases

Alex

Answer:

different acids include acetic acid,lactic acid,tartaric acids DNA(deoxyribonucliec acid) .

different bases include calcium oxide Potassium hydroxide ,Sodium hydroxide and Barium hydroxide .

5 0

3 years ago

In 2.00 min, 29.7 mL of He effuse through a small hole. Under the same conditions of pressure and temperature, 9.28 mL of a mixt

sergiy2304 [10]

Answer : The percent composition by volume of mixture of $CO$ and $CO_2$ are, 18.94 % and 81.06 % respectively.

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

$R\propto \sqrt{\frac{1}{M}}$

And the relation between the rate of effusion and volume is :

$R=\frac{V}{t}$

or, from the above we conclude that,

$(\frac{V_1}{V_2})^2=\frac{M_2}{M_1}$ ..........(1)

where,

$V_1$ = volume of helium gas = 29.7 ml

$V_2$ = volume of mixture = 9.28 ml

$M_1$ = molar mass of helium gas = 4 g/mole

$M_2$ = molar mass of mixture = ?

Now put all the given values in the above formula 1, we get the molar mass of mixture.

$(\frac{29.8ml}{9.28ml})^2=\frac{M_2}{4g/mole}$

$M_2=40.97g/mole$

The average molar mass of mixture = 40.97 g/mole

Now we have to calculate the percent composition by volume of the mixture.

Let the mole fraction of $CO$ be, 'x' and the mole fraction of $CO_2$ will be, (1 - x).

As we know that,

$\text{Average molar mass of mixture}=\text{Mole fraction of }CO$

$\text{Average molar mass of mixture}=(\text{Mole fraction of }CO\times \text{Molar mass of } CO)+(\text{Mole fraction of }CO_2\times \text{Molar mass of } CO_2)$

Now put all the given values in this expression, we get:

$40.94g/mole=((x)\times 28g/mole)+((1-x)\times 44g/mole)$

$x=0.1894$

The mole fraction of $CO$ = x = 0.1894

The mole fraction of $CO_2$ = 1 - x = 1 - 0.1894 = 0.8106

The percent composition by volume of mixture of $CO$ = $0.1894\times 100=18.94\%$

The percent composition by volume of mixture of $CO_2$ = $0.8106\times 100=81.06\%$

Therefore, the percent composition by volume of mixture of $CO$ and $CO_2$ are, 18.94 % and 81.06 % respectively.

6 0

3 years ago

3.Write the symbol of the element that has a charge of +1 when it has 71 electrons.

tigry1 [53]

The symbol : $\tt _{72}^{178}Hf^{+1}$

<h3>Further explanation </h3>

There are two components that accompany an element, the mass number and atomic number

Atoms are composed of 3 types of basic particles (subatomic particles): <em>protons, electrons, and neutrons </em>

The Atomic Number (Z) indicates the number of protons and electrons in an atom of an element.

Atomic number = number of protons = number of electrons ⇒ neutral number

Atomic mass is the sum of protons and neutrons

Atomic Number (Z) = Atomic mass (A) - Number of Neutrons

The element has 71 electrons and a charge of +1 , so

Number of protons = 71 + 1 = 72

Number of protons = the atomic number = 72

The element with atomic number 72 is Hafnium(Hf)

The atomic mass of Hf = 178 g/mol

4 0

3 years ago