The minimum potential difference must be supplied by the ignition circuit to start a car is -1800 V
<u>Explanation:</u>
Given data,
E= 3 ×10 ⁶ Δx=0.06/100
We have to find the minimum potential difference
E= -ΔV/Δx
ΔV=- E × Δx
ΔV =-3 ×10 ⁶ . 0.06/100
ΔV=-1800 V
The minimum potential difference must be supplied by the ignition circuit to start a car is -1800 V
Answer:
Satellite D has a mass (kg) of 500 and the distance from Earth (km) is 320.
Explanation:
The universal law of gravitation states that the force between two objects in the universe is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
We have to choose the satellite having greatest gravitational force with earth. In all options the distance from the earth is same i.e. 320 km. So, we have to select the satellite having maximum mass because the mass of the earth is constant.
Hence, the correct option is (D) " Satellite D has a mass (kg) of 500 and the distance from Earth (km) is 320 ".
Heat stroke had occurred when your body can no longer regulate its temperature. hope it helps :)
Force = 3200 N
Work done = 640, 000 Nm
Explanation:
We begin by calculating the deceleration of the truck, using the velocity and distance;
a = (v² – u²)/2s
whereby;
a = acceleration
v = initial velocity
u = initial velocity
s = distance
We begin by changing the speed from km/h into m/s;
54km/hr = 15m/s
Then acceleration;
a = (0² – 15²) / 2 * 200
a = -225 / 400
a = - 0.5625 m/ s²
To calculate force;
F = ma
Whereby;
F = force
M = mass (in kgs)
a = acceleration
F = 1800 / 0.5625
F = 3200 N
Work done = Force * displacement
Work done = 3200 * 200
= 640, 000 Nm
Learn More:
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