Question

Using the equation, 4Fe + 3O2 Imported Asset 2Fe2O3, if 8 moles of iron and oxygen from the air were available, how many moles of iron (III) oxide would be produced?
4 moles

5 moles

6 moles

8 moles

Answer 1

From the balanced chemical equation,
                               4Fe + 3O₂ --> 2Fe₂O₃
it is evident that for every 4 moles of Fe (iron), 2 moles of iron (III) oxide will be formed. Using the same ratio, 
                               8 moles of iron x (2 moles Fe₂O₃ / 4 moles of Fe)
                                         = 4 moles Fe₂O₃
Therefore, the answer is 4 moles. 

Answer 2

Answer: The correct answer is 4 moles.

Explanation:

For the given chemical reaction:

$4Fe+3O_2\rightarrow 2Fe_2O_3$

Oxygen from air is available which means it is present in excess. Iron is considered as a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

4 moles of iron produces 2 moles of iron oxide.

So, 8 moles of iron will produce = $\frac{2}{4}\times 84mol$ of iron oxide.

Hence, the correct answer is 4 moles.