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Firdavs [7]
3 years ago
10

I need help with 3&4 ...

Mathematics
2 answers:
Montano1993 [528]3 years ago
8 0
2*5=10 is the answer
scZoUnD [109]3 years ago
6 0
General form for circle is 
(x - a)^2 + (y - b)^2 = r^2

so if center is at (3,-2) we can plug in a and b:-

(x-3)^2 + (y+2)^2 = r^2

Now plug in x = 7 and y =1  (from the point R)

4^2 + 3^2 = r^2 
r^2 =  25  making r = 5

so its diameter = 2*5 = 10
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Leviafan [203]

Answer:

the order of operations is .called BODMAS rule

B.brackets

O.of

D.division

M.multiplication

A.addition

S.subtraction

Step-by-step explanation:

= (-112)-(20)

= -132

6 0
3 years ago
A turtle and a snail are 300 feet apart when they start moving towards each other. The turtle is moving at a speed of 5 feet per
givi [52]

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Help with Algebra 2: 1. <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E5%7D%20%7D%7B%5Csqrt%5B4%5D%7Bx%5E2%7D%
Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

1. Given the expression

\dfrac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }

Note that

\sqrt[7]{x^5}=x^{\frac{5}{7}} \\ \\\sqrt[4]{x^2}=x^{\frac{2}{4}}=x^{\frac{1}{2}}

When dividing \sqrt[7]{x^5} by \sqrt[4]{x^2}, we have to subtract powers (we cannot subtract 4 from 7, because then we get another expression), so

\dfrac{5}{7}-\dfrac{2}{4}=\dfrac{5}{7}-\dfrac{1}{2}=\dfrac{5\cdot 2-1\cdot 7}{14}=\dfrac{3}{14}

and the result is x^{\frac{3}{14}}=\sqrt[14]{x^3}

2. Given equation 3\sqrt[4]{(x-2)^3} -4=20

Add 4:

3\sqrt[4]{(x-2)^3} -4+4=20+4\\ \\3\sqrt[4]{(x-2)^3}=24

Divide by 3:

\sqrt[4]{(x-2)^3} =8

Rewrite the equation as:

(x-2)^{\frac{3}{4}}=8\\ \\(x-2)^{\frac{3}{4}}=2^3

Hence,

\left((x-2)^{\frac{3}{4}}\right)^{\frac{4}{3}}=(2^3)^{\frac{4}{3}}\\ \\x-2=2^{3\cdot \frac{4}{3}}\\ \\x-2=2^4\\ \\x-2=16\\ \\x-2+2=16+2\\ \\x=18

3 0
3 years ago
What is the sequence technique of this number sequence 3 20 78 334 1696 ?
polet [3.4K]
3×2+14=20
20×3+18=78
78×4+22=334
334×5+26=1696
1696×6+30=10206
Hence, the question mark should be replaced by 10206
3 0
3 years ago
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