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eimsori [14]
3 years ago
6

The frequency of light emitted from a source is changed. What visible evidence would indicate this?

Physics
2 answers:
Dvinal [7]3 years ago
7 0

Answer: If the light is visible, you would notice a change in the colour of the light.  The frequency of a light ray is relationed with the wavelength in the next way λ = v/f.

where λ is the wavelength, v is the speed of the light ( in this case is c) and f is the frequency.

The visible wavelength are in the range of 380 nm to 750 nm

where 380 nm is a blue extreme, and the 750 nm is the "red" extreme.

Then if your frequency decreases, your wavelength increases and the light turns more reddish, if your frequency increases, your wavelength decreases and the light turns more blueish.

Llana [10]3 years ago
5 0
The change of color. Each color has a different wavelength therefore a different frequency.
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Why doesn't an object thrown in an upward direction fall the same distance in each time interval as it descends toward Earth? (A
Stels [109]
I'm not that smart but I think it is c I really hope It helps
4 0
3 years ago
Please help asap its for anatomy
Brilliant_brown [7]

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Read more about Micturition here brainly.com/question/26493943

6 0
2 years ago
A small block of mass M = 0.10 kg is released from rest at point 1 at a height H = 1.8 m above the bottom of a track, as shown i
Ede4ka [16]

Answer:

D

Explanation:

A) is not correct, because the gravitation potential energy will depend on the height the block is located at. It will be calculated with the formula:

U=mgh.

If we take the ground as a zero height reference, then on point 2 the potential energy will be:

U_{2} = 0.10kg(9.81 m/s^{2})(0.6m)

U_{2}=0.59 J

While on point 3, the potential energy will be greater.

U_{3}=0.10kg(9.81 m/s^{2})(1.2m)

U_{3}=1.18 J

B) is not the right answer because the kinetic energy will vary with the height the block is located at in the fact that the energy is conserved (this is if we don't take friction into account or air resistance) so in this case:

U_{2}+K_{2}= U_{3}+K_{3}

We already know the potential energy at point 2. We can calculate the kinetic energy at point 3 like this:

K_{3} =\frac{1}{2}mv_{3}^{2}

K_{3} =\frac{1}{2}(0.10kg)(2.5 m/s)^{2}

K_{3} =0.31 J

So the kinetic energy at point 2 is given by the equation:

K_{2}  =U_{3}-U_{2}+K_{3}

so:

K_{2} = (1.18J)-(0.59J)+0.31J

K_{2} =0.9J

As you may see the kinetic energy at point 2 is greater than the kinetic energy at point 3.

C) Is not correct because according to the first law of thermodinamics, energy is not lost, only transformed. So, since we are not taking into account friction or any other kind of loss, then we can say that the amount of mechanical energy at point 1 is exactly the same as the mechanical energy at point 3.

D) Because of what we talked about on part C, this will be the true situation, because the mechanical energy of the block will be the same no matter theh point you measure it at.

7 0
3 years ago
the particles that make up a rock are constantly in motion however a rock does not visibly vibrate. why do you think this?
Ivahew [28]

I think this is because the particles don't know or care about each other,
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as any other direction for the next vibration, and they all wind up vibrating in
different directions.  There is a tiny tiny tiny tiny chance that all of them could
vibrate in the same direction for just an instant; if that ever happened, the rock
would suddenly jump up in the air.  That's actually true, but the chance is so tiny
that it hasn't ever happened yet.  In fact, the chance is so tiny, that when scientists
do their calculations of particle vibrations, they assume that the chance is zero,
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3 0
3 years ago
Help please !!<br>I need help with this!
belka [17]
Hello Again! I think the Answer might be 220 m! ( 1/2) ( 21 m/s + 0 m/s) (21 s) = 220 m
6 0
3 years ago
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