Complete question:
Consider the hypothetical reaction 4A + 2B → C + 3D
Over an interval of 4.0 s the average rate of change of the concentration of B was measured to be -0.0760 M/s. What is the final concentration of A at the end of this same interval if its concentration was initially 1.600 M?
Answer:
the final concentration of A is 0.992 M.
Explanation:
Given;
time of reaction, t = 4.0 s
rate of change of the concentration of B = -0.0760 M/s
initial concentration of A = 1.600 M
⇒Determine the rate of change of the concentration of A.
From the given reaction: 4A + 2B → C + 3D
2 moles of B ---------------> 4 moles of A
-0.0760 M/s of B -----------> x
⇒Determine the change in concentration of A after 4s;
ΔA = -0.152 M/s x 4s
ΔA = -0.608 M
⇒ Determine the final concentration of A after 4s
A = A₀ + ΔA
A = 1.6 M + (-0.608 M)
A = 1.6 M - 0.608 M
A = 0.992 M
Therefore, the final concentration of A is 0.992 M.
Answer:
magnitude of the gravitational force is 9.04 × N
Explanation:
given data
altitude = A = 612 km = 612000 m
mass M = 11,100 kg
mass of the Earth m = 5.97 × kg
Earth average radius = 6.38 × m
to find out
magnitude of the gravitational force
solution
first we get here distance from space to centre of earth that is
distance = altitude + earth radius
distance = 612000 + 6.38 × m
distance = 6.99 × m
so now we get here magnitude of the gravitational force that is express as
magnitude of the gravitational force F = ...........1
here G is gravitational constant that is 6.67 × Nm² /kg and M is mass of space and m is mass of earth
put here all value we get
F =
F =
F = 9.04 × N
so magnitude of the gravitational force is 9.04 × N
They mostly affect it negatively. Often times, urban populations can overcrowd, overuse or pollute a water supply. Take the river Thames for example, in London. It's used so much that its waters are hardly safe to swim in, much less drink. Also, we cram water in reservoirs, making it safe for us, but keeping local wildlife from it.
Have a great night/day!
-Dylan (AKA Animus
Without the velocity of the wave you can't get the frequency.
-- The maximum horizontal force without moving the crate
depends on the friction along the surface where the crate
meets the floor.
That force will be greater if the crate and the floor are both lined
with sandpaper, and it will be less if there is a layer of oil between
them. We don't know anything about those surfaces.
If ' μ ' is the coefficient of static friction between the crate and the floor,
then the force of friction acting opposite to a horizontal push is
( μ )·( mass )·( gravity )
= ( μ )·( 136 kg )·( 9.8 m/s² )
= 1,332.8μ Newtons.
A push less than this will not move the crate.
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-- " m/s² " is a unit of acceleration, not a unit of force.
Once the crate starts to slip, its behavior depends on the coefficient
of KINETIC friction between it and the floor, which we also don't know,
but this number is usually smaller than the static coefficient. So the
force of friction will decrease once the crate starts to slip, and you're
correct in expecting that it'll accelerate in the direction of the push,
even though the strength of the push doesn't change. Again, we
can't estimate the magnitude of the acceleration without knowing the
nature of the friction where the crate meets the floor.