Answer:
0.25 m/s
Explanation:
This problem can be solved by using the law of conservation of momentum - the total momentum of the squid-water system must be conserved.
Initially, the squid and the water are at rest, so the total momentum is zero:
After the squid ejects the water, the total momentum is
where
is the mass of the squid
is the velocity of the squid
is the mass of the water
is the velocity of the water
Due to the conservation of momentum,
so
so we can find the final velocity of the squid:
and the negative sign means the direction is opposite to that of the water.
Answer:
P=4801.5
Explanation:
Given :
work done = W = 100,832 J
time = 21.0 sec
Find:
P = ?
Formula:
P = W/t
Solution:
P = W/t
P = 100,832/21.0
= 4801.52 J/s or Watts
Answer:
19.8 J
Explanation:
According to the law of conservation of energy, the total mechanical energy of the spring (sum of kinetic energy and elastic potential energy) must be conserved:
(1)
where we have
is the initial kinetic energy of the spring, which is zero because the spring starts from rest (2)
is the elastic potential energy of the spring when it is fully stretched
is the kinetic energy of the spring when it reaches the natural length
is the elastic potential energy of the spring when it reaches its natural length, which is zero because the stretch in this case is zero (3)
So
where
k = 440 N/m is the spring constant
is the initial stretching of the spring
Substituting,
And so using eq.(1) and keeping in mind (2) and (3) we find
Answer:
M g H = 1/2 M v^2 potential energy = kinetic energy
v^2 = 2 g H = 2 * 9.80 * 6 = 117.6 m/s^2
v = 10.8 m/s
(C)
Increase. The Law of Boyle and Gay Lussac subscribes that when the pressure remains constant, V/T is constant. So if T rises, so must V to keep the number constant.
