The electric field at any point in the region between the conductors is proportional to the magnitude Q of charge on each conductor. It follows that:
"The potential difference Vab between the conductors is also proportional to Q"
If we double the magnitude of charge on each conductor, the charge density at each point doubles, the electric field at each point doubles, and the potential difference between conductors doubles; however, the ratio of charge to potential difference does not change. This ratio is called the capacitance C of the capacitor:

Given that:

and
Lastly, the capacitance is given by:
In order to make an electric current flow it is necessary to have a source of the current or source of free electrons and also the circuit should be a close one or complete. When there is a break in a circuit, no current would flow in the whole system.
answer
77.25 N
explanation
(look at picture for free body diagram)
the force on the piano has both vertical and horizontal components, and since the questions asks about the force to lift the piano, we want to find the vertical component
we can use trigonometry where sinA = opposite/hypotenuse
A = 18 degrees
hypotenuse = 250 N
sin18 = opposite (vertical component) / 250
vertical component = sin18 * 250
= 77.25 N
The magnitude of the magnetic field on the axis of the ring 5 cm from its center is 143 pT.
The radius of the nonconducting ring is R = 10 cm.
The ring is uniformly charged q = 10 μC.
The angular speed of the ring, ω = 20 rad/s
The ring is x = 5 cm from the center of the ring.
Now,
R = 10 cm = 0.1 m
q = 10.0 μC = 10 × 10⁻⁶ C
x = 5 cm = 0.05 m
The magnetic field on the axis of a current loop is given as:
B = [ μ₀ IR² ] / [4π(x² + R²)^{3/2} ]
Now, I = q / [2π/ω]
So, the magnitude of the magnetic field which is directed away from the center is:
B = [ μ₀ ωqR² ] / [4π(x² + R²)^{3/2} ]
B = [ μ₀ (200) (10 × 10⁻⁶) (0.1)² ] / [4π((0.05)² + (0.1)²)^{3/2} ]
B = 1.43 × 10⁻¹⁰ T
B = 143 pT
Learn more about the magnetic field here:
brainly.com/question/14411049
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