Question

In a pipe closed at one end and filled with air, a 384-Hz tuning fork resonates when the pipe is 22-cm-long; this tuning fork

Answer 1

Answer:

Three other length for which resonance will occur is 66 cm, 110 cm and 154 cm

Explanation:

As we know that the length of the pipe is 22 cm

Now let say it is in 1st harmonic state so we have

$\frac{\lambda}{4} = L$

so we have

$\frac{\lambda}{2} = 2L$

So we have

$L_1 = L + \frac{\lambda}{2}$

$L_1 = L + 2L$

$L_1 = 22 + 2L$

For N = 1

$L_1 = 66 cm$

For N = 2

$L_2 = 22 + 88$

$L_2 = 110 cm$

For N = 3

$L_3 = 22 + 132$

$L_3 = 154 cm$