That's electric "current", usually described in 'Amperes'.
1 Ampere = 1 Coulomb per second ... "the rate at which
charge passes a point in the circuit".
X=bt + ct3, b=1.50m/s, c=0.640m/s3.
Average velocity = distance / time
ti = 1.00, tf = 3.00
xi = (1.50)(1.00) + (0.640 )(1.00)^3 = 1.5 + 0.640 = 2.14 m
xf = = (1.50)(3.00) + (0.640)(3.00)^3 = 4.5 + 27(17.28) = 21.78 m
Ave Velocity = (21.78 - 2.14) / (3 - 1) = 9.82 m/s
Answer:
i) 0.9504
ii) 0.0452
Explanation:
Given data: reliability of hydraulic brakes= 0.96
reliability of mechanical brakes = 0.99
So the probability of stopping the truck = 0.96×0.99= 0.9504
At low speed
case: A works and B does not
= 0.96×(1-0.99) = 0.0096
case2 : B works and A does not
= 0.99×(1-0.96) = 0.0396
Therefore, probality of stopping = 0.0096+0.0396 = 0.0492
The answer is B. 79 joules.
To calculate this we will use the formula for potential energy (PE):
PE = m * g * h
where m is mass of an object, g is gravitational acceleration, h is a height at which is the object.
It s given:
m = 8.10 kg
g = 9.8 m/s²
h = 0.99 m
After replacing them in the formula for potential energy:
PE = 8.10 * 9.8 * 0.99 = 78.6 J ≈ 79 J