All categories

2 years ago

Speed is the ratio of the distance an object moves to

Physics

2 answers:

zaharov [31]2 years ago

8 0

The correct answer is A. The amount of time needed to travel the distance

Explanation:

Speed focuses on measuring how fast an object moves through the formula Speed = Distance / Time. For example, if a car traveled 150 km in 3 hours the speed is 50 km/h considering 150 km (distance) divided into 3 hours (time) equals 50km/h (speed). This implies speed considers both the distance the object moves and the time that takes this movement. Moreover, speed does not focus on the direction of the movement or any other factors. Thus, speed is the ratio of the distance an object moves to "the amount of time needed to travel the distance".

guajiro [1.7K]2 years ago

6 0

A - the amount of time needed to travel the distance

The formula for speed is distance/time and the unit is m/s. Therefore you divide the distance travelled by the time it took to travel it.

You might be interested in

A 53.0-kg skater is traveling due east at a speed of 2.90 m/s. A 72.0-kg skater is moving due south at a speed of 6.20 m/s. They

soldier1979 [14.2K]

Answer:

a. $\thta=71^{\circ}$

b. $v_f=3.78 m/s$

Explanation:

We are given that

$m_1=53 kg$

$v_1=2.9 m/s$

$m_2= 72 kg$

$v_2=6.2 m/s$

a.We have to find the angle

$\theta=tan^{-1}{\frac{m_2v_2}{m_1v_1}=\frac{72(6.2)}{53(2.9)}=71^{\circ}$

$\theta=71^{\circ}$

b. We have to find the speed $v_f$

According to law of conservation of momentum

$m_1v_1=(m_1+m_2)v_fcos\theta$

$53(2.9)=(53+72)v_fcos 71^{\circ}=40.7 v_f$

$v_f=\frac{153.7}{40.7}=3.78 m/s$

3 0

2 years ago

Which of the following is most closely related to an activated complex?

Anon25 [30]

Among the choices above, the one that is most closely related to an activated complex is the transition state. The answer is letter D. This formation forms quickly and does not stay in a way compound is. It usually forms during the enzyme – substrate reaction.

5 0

3 years ago

A small boat coasts at constant speed under a bridge. A heavy sack of sand is dropped from the bridge onto the boat. The speed o

Tju [1.3M]

Answer:

d. decreases

Explanation:

The law of conservation of momentum tells us that the sum of momenta before the collision is equal to the sum of momenta after the collision. The bag has no momentum as it falls onto the boat because its velocity is zero in the horizontal direction. But after it hits the boat, it's momentum increases while the momentum of the system remains the same. That means a component of the system must decrease somewhere else. And that component is the velocity, not the mass, of the boat.

7 0

3 years ago

How do you find the force of gravity?

devlian [24]

1Define the equation for the force of gravity that attracts an object, Fgrav = (Gm1m2)/d2
2. Use the proper metric units.
3. Determine the mass of the object in question.
4. Measure the distance between the two objects
5. Solve the equation

7 0

3 years ago

A spring of spring constant 30.0 N/m is attached to a 2.3 kg mass and set in motion. What is the period and frequency of vibrati

coldgirl [10]

Answer:

1. The period is 1.74 s.

2. The frequency is 0.57 Hz

Explanation:

1. Determination of the the period.

Spring constant (K) = 30 N/m

Mass (m) = 2.3 Kg

Pi (π) = 3.14

Period (T) =?

The period of the vibration can be obtained as follow:

T = 2π√(m/K)

T = 2 × 3.14 × √(2.3 / 30)

T = 6.28 × √(2.3 / 30)

T = 1.74 s

Thus, the period of the vibration is 1.74 s.

2. Determination of the frequency.

Period (T) = 1.74 s

Frequency (f) =?

The frequency of the vibration can be obtained as follow:

f = 1/T

f = 1/1.74

f = 0.57 Hz

Thus, the frequency of the vibration is 0.57 Hz

4 0

3 years ago