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a].<u>When sand is added to water it either hangs in the water or forms a layer at the bottom of the container. Sand therefore does not dissolve in water and is insoluble. It is easy to separate sand and water by filtering the mixture. </u>
<u>b</u><u>]</u><u>.</u><u> </u><u>T</u><u>h</u><u>e</u><u> </u><u>w</u><u>a</u><u>t</u><u>e</u><u>r</u><u> </u><u>f</u><u>i</u><u>l</u><u>t</u><u>e</u><u>r</u><u>e</u><u>d</u><u> </u><u>b</u><u>y</u><u> </u><u>k</u><u>a</u><u>m</u><u>a</u><u>l</u><u> </u><u>i</u><u>s</u><u> </u><u>n</u><u>o</u><u>t</u><u> </u><u>s</u><u>a</u><u>f</u><u>e</u><u> </u><u>t</u><u>o</u><u> </u><u>d</u><u>r</u><u>i</u><u>n</u><u>k</u><u> </u><u>.</u>
<u>If you run out of water, or cannot carry enough water with you for your entire trip, you may need to source drinking water from natural water sources.</u>
Hey there,
Based on my research and my understanding, your correct answer would be exactly 760 torr. Because if you do <span>Pt = P1 + P2 + P2, that will eventaully give your 760 torr.
~Jurgen</span>
Answer:
It is an example of coupling an exogenic reaction to an endogenic reaction.
Explanation:
The endergonic reaction is typically being pushed by coupling it to strongly exergonic reaction. This is in most cases via shared intermediates. Most chemical reactions are endergonic in nature. In other word, the are not spontaneous (i.e ΔG>0). Energy must also be applied externally to initiate the reactions. The reactions can also be coupled to exergonic reactions (with ΔG<0) to initiate them through a process known as share intermediate. Because Gibbs Energy can be summed up (i.e is a state function), the combined ΔG of the coupled reaction will be thermodynamically favorable. The decomposition of calcium carbonate is a typical example.
Answer:
x=170
The question is asking you to add them together to get your unknown number
Electrons hold a negative charge, and anion refers to a negatively charged atom.
The answer is anion. Here's a way to help remember:
Cats have paws, and cations are "paws"itive (positive).