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otez555 [7]
3 years ago
9

If you place a 4.00 g effervescent antacid pill into 85 mL (85 g ) of water in a 90 g glass, how much will the glass of water we

igh once the antacid pill has dissolved?
Chemistry
1 answer:
nikdorinn [45]3 years ago
5 0

Answer:

The glass of water weigh once the antacid pill has dissolved will be less than the 179 grams due to evolution of carbon dioxide.

Explanation:

Mass of effervescent antacid pill = 4.00 g

Mass of water = 85 g

Mass of glass = 90 g

Total mass of the substances  together : 4.00 g + 85 g + 90 g = 179 g

Effervescent antacid pill , moment it get dissolved in water carbon dioxide gas is evolves and escape from the solutions.

This means that mass of the weight of the glass of water with antacid dissolved in it will be less than 179 grams.

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Answer:

See explanation

Explanation:

Potassium is a metal. Remember that metals are electropositive in nature. This implies that they give out electrons when they undergo ionic bonding with nonmetals.

Chlorine is a nonmetal. So the bond between chlorine and potassium is ionic.  Potassium gives out one electron to chlorine and the both ions now attain a stable octet.

The electronic configuration of potassium is [Ar]4s1. After giving out an electron to chlorine in an ionic bond, its electronic configuration is now [Ar].

3 0
2 years ago
Automotive air bags inflate when sodium azide, NaN3, decomposes explosively to its constituent elements. How many moles of nitro
attashe74 [19]

Answer:

2.29 g of N2

Explanation:

We have to start with the <u>chemical reaction</u>:

NaN_3~->~Na~+~N_2

The next step is to <u>balance the reaction</u>:

2NaN_3~->~2Na~+~3N_2

We can continue with the <u>mol calculation</u> using the molar mass of

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3.55~g~NaN_3\frac{1~mol~NaN_3}{65~g~NaN_3}=0.054~mol~NaN_3

Now, with the<u> molar ratio</u> between NaN_3  and N_2  we can <u>calculate the moles</u> of N_2  (2:3), so:

0.054~mol~NaN_3\frac{3~mol~N_2}{2~mol~NaN_3}=0.0819~mol~N_2

With the molar mass of N_2 we can <u>calculate the grams</u>:

0.0819~mol~N_2=\frac{1~mol~N_2}{28~g~N_2}=2.29~g~N_2

I hope it helps!

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3 years ago
Please help me I will give you the brain thing and extra points. image below part
jekas [21]
D is the correct answer... if u need in depth let me know
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2 years ago
which of the following is an example of an electromagnetic wave A. an ocean wave B. A sound wave C. A light wave D. A wave trave
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