When there are lone pairs on the valence shell of the central atom in a molecule, the bond angle is decreased.
The shape of molecules depend on the number of electron pairs on the valence shell of the molecules. These electron pairs could be lone pairs or bond pairs. Lone pairs occupy more space around the central atom since it is attracted to only one nucleus compared to bond pairs which are attracted to two nuclei.
When lone pairs are present on the central atom in a molecule, they tend to "squeeze" the molecule thereby decreasing the bond angle in the molecule. Hence, presence of one or more lone pairs of electrons make the bond angles get smaller.
Learn more: brainly.com/question/10079361
Answer : The correct option is, (e) eg = trigonal planar, mg = trigonal planar
Explanation :
Formula used :
![\text{Number of electron pair}=\frac{1}{2}[V+N-C+A]](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20electron%20pair%7D%3D%5Cfrac%7B1%7D%7B2%7D%5BV%2BN-C%2BA%5D)
where,
V = number of valence electrons present in central atom
N = number of monovalent atoms bonded to central atom
C = charge of cation
A = charge of anion
The given molecule is, 
![\text{Number of electron pair}=\frac{1}{2}\times [4+3-1]=3](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20electron%20pair%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%5B4%2B3-1%5D%3D3)
That means,
Bond pair = 3
Lone pair = 0
The number of electron pair are 3 that means the hybridization will be 
and the electronic geometry of the molecule will be trigonal planar.
Hence, the electron geometry (eg) and molecular geometry (mg) of is, trigonal planar and trigonal planar respectively.
Firstly calculate the grams in the last 8 percent before moving onto the pyrite section.
50.8x0.08=4.064g
We know that iron ore in this case has 92 percent pyrite which contains 46.5 percent iron so we do 50.8x0.92=46.736g from this we need to find 46.5 percent of the iron content in the 92 percent pyrite section then add this answer to the 8 percent of iron ore we found at the start.46.736x0.465=21.73224g
21.73224g+4.064=25.79624g of iron ore 25.8g(3sf)
After careful consideration your answer is...
Leucippus and Democritus
*Hope I helped*
~Alanna~
