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alexdok [17]
2 years ago
13

A student uses 0.0821 L• atm/mol • K as the value of the gas constant. What is most likely true about the variables in the ideal

gas law?
P has the units of liters • atmospheres, and T has the units of kelvin.

P has the units of liters • atmospheres, and T has the units of degrees Celsius.

V has the units of liters, and T has the units of kelvin.

V has the units of liters, and T has the units of degrees Celsius.
Chemistry
2 answers:
Ray Of Light [21]2 years ago
7 0
Considering P represents pressure why god would it be measured in liters. Ignore the first 2 choices.
With all gas law related questions you never use Celsius temperatures.
The answer has to be V has units of liters, and T has the units of kelvin.
serious [3.7K]2 years ago
4 0

Answer is: V has the units of liters, and T has the units of kelvin.

Ideal gas law: p·V = n·R·T.  

atm · L = mol · L·atm/mol·K · K; both side of equatation have same values.

R = 0,08206 L·atm/mol·K; universal gas constant.  

p is pressure of the gas, unit is standard atmosphere (atm).

V is volume of the gas, unit is liters (L).

n is amount of substance of the gas; unit is mole (mol).

T is temperature of the gas, unit is Kelvin (K).

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How much heat energy is required to convert 48.3 g of solid ethanol at -114.5 degree C to gasesous ethanol at 135.3 degree C? Th
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Answer:

7.21 × 10⁴ J

Explanation:

Ethanol is solid below -114.5°c, liquid between -114.5°C and 78.4°C, and gaseous above 78.4°C.

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We need to calculate the heat required in different stages and then add them.

The moles of ethanol are:

48.3g.\frac{1mol}{46.07g} =1.05mol

Solid-liquid transition

Q₁ = ΔHfus . n = (4.60 kJ/mol) . 1.05 mol = 4.83 kJ = 4.83 × 10³ J

where,

ΔHfus: molar heat of fusion

n: moles

Liquid: from -114.5°C to 78.4°C

Q₂ = c(l) . m . ΔT = (2.45 J/g.°C) . 48.3g . [78.4°C-(-114.5°C)] = 2.28 × 10⁴ J

where,

c(l): specific heat capacity of the liquid

ΔT: change in the temperature

Liquid-gas transition

Q₃ = ΔHvap . n = (38.56 kJ/mol) . 1.05 mol = 40.5 kJ = 40.5 × 10³ J

where,

ΔHvap: molar heat of vaporization

Gas: from 78.4°C to 135.3°C

Q₄ = c(g) . m . ΔT = (1.43 J/g.°C) . 48.3g . (135.3°C-78.4°C) = 3.93 × 10³ J

where

c(g): specific heat capacity of the gas

Total heat required

Q₁ + Q₂ + Q₃ + Q₄ = 4.83 × 10³ J + 2.28 × 10⁴ J + 40.5 × 10³ J + 3.93 × 10³ J = 7.21 × 10⁴ J

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Answer:

0.0738 M

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