Primary amines can be prepared from nitriles by reduction with LiAlH4. The two-step sequence involves SN2 displacement of halide
ion by cyanide ion followed by reduction, and yields a primary amine with one more carbon than was present in the alkyl halide. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions
1 answer:
Answer:
See explanation below
Explanation:
You are not putting the mechanism step you want to be explained. I found this question, and it's attached on picture 1.
According to that, we do have a Aryl halide, reacting with cyanide ion, and then, LiAlH4.
The first step is a Sn2 reaction where the cyanide ion displace the Bromide. The second step is the reduction, which is a long step mechanism, and this is shown in pícture 2. At the end of this step, we already has added a CH2 in the molecule, and the water will allow to reduce the N group with the AlH3 to the respective primary amine.
See picture below for explanation of the mechanism
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Answer:
Explanation:
= Initial volume = 100 mL
= Final volume = 1000 mL
= Initial concentration = 0.5 M
= Final concentration
We have the relation
The new concentration is .
Answer:
Explanation has been given below
Explanation:
- In diaxial conformation of cis-1,3-disubstituted cyclohexane, 4 gauche-butane interactions along with syn-diaxial interaction are present. Hence it readily gets converted to diequitorial conformation where no such gauche-butane interaction is present
- In two possible conformations of trans-1,3-disubstituted cyclohexane, 2 gauche-butane interactions are present in each of them.
- Hence cis-1,3-disubstituted cyclohexane exists almost exclusively in diequitorial form. But trans-1,3-disubstituted cyclohexane has no such option.
- Trans-1,3-disubstituted cyclohexane experiences gauche butane interaction in each of the two conformations.
- Therefore cis-1,3-disubstituted cyclohexane is more stable than trans conformation
