Answer:
A molecule can be defined as the combinations of two or more atoms are held together by chemical bonds. A molecule is the smallest portion of a substance which showcases all the properties of the substance.
Explanation:
Answer: The mole fraction of neon in the final mixture is 0.6
Explanation:
According to Dalton's law, the total pressure is the sum of individual pressures.
Given :
=total pressure of gases = 5.0 atm
= partial pressure of argon = 2.0 atm
= partial pressure of Neon = ? atm
According to Raoults law, the partial pressure of a gas is equal to its mole fraction mulitiplied by the total pressure.

= mole fraction of Neon


Thus mole fraction of neon in the final mixture is 0.6
Answer:
Tetrahedral electron geometry and trigonal pyramidal molecular geometry.
Explanation:
The Lewis structure is shown in Figure 1.
The central N atom has three bonding pairs and one lone pair, for <em>four electron groups</em>.
VSEPR theory predicts a tetrahedral electron geometry with bond angles of 109.5°.
We do not count the lone pair in determining the molecular shape.
The molecular geometry is trigonal pyramidal (see Figure 2).
Answer:
Explanation:
[ H⁺] = 3.5 x 10⁻⁶ M .
[ H⁺] [ OH⁻] = 10⁻¹⁴
[ OH⁻] x 3.5 x 10⁻⁶ = 10⁻¹⁴
[ OH⁻] = 2.857 x 10⁻⁹ M .
Answer:
the specific heat of the sample is c sam = 0.42 J/g °C
Explanation:
if we assume that the sample is submerged into the mixture, such that all the heat released by the sample is absorbed by the ice and water, and there is no time to the heat to be released to the surroundings ( or the system is isolated):
Q ice wat + Q sam = Q surroundings = 0
Q ice wat= - Q sam
since the ice-water mixture remains, the final temperature is 0°C (water-ice equilibrium), thus only latent heat is involved
Assuming that there is no heat due to reaction or phase change of the sample, the heat released is only sensible heat
Q sam = m sam * c sam ( T final - T initial )
Q ice wat = m ice * ΔH fusion / M water
therefore
- m sam * c sam ( T final - T initial ) = m ice * ΔH fusion / M water
c sam= m ice * ΔH fusion /[ m sam * M water *( T initial - T final )]
replacing values
c sam = 110.6 g * 6.02 kJ/mol / ( 452.3 g * 18 gr/mol*( 192°C -0°C) * 1000 J/kJ = 0.42 J/g °C
thus
c sam = 0.42 J/g °C