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Mass or part divided my molecular mass
Balance the equation first:
2 Fe+6 HNO3→2 Fe(NO3)3+3H2
Then calculate mass of Iron :
4.5×3.0×3.5 cm3(1 mL1 cm3)(7.87 g Fe1 ml)=371.86 g Fe
Now use Stoichiometry:
371.86 g Fe×(1 mol Fe55.85 g Fe)×(6 mol HNO32 mol Fe)=19.97 mol HNO3
Convert moles of nitric acid to grams
19.97 mol HNO3×(63.01 g HNO31 mol HNO3)=1258.3 g HNO3
Answer:
Explanation:
1)
H₂SO₄:
Element (symbol) No of atoms in No of compounds Total atoms
1 molecule coefficient
H 2 1 2
S 1 1
O 4 4
2)
2H₃PO₄:
Element (symbol) No of atoms in No of compounds Total atoms
1 molecule coefficient
H 3 2 6
P 1 2
O 4 8
There are two mole of H₃PO₄. One mole contain 3 hydrogen atom, 1 phosphorus atom and 4 oxygen atoms. Thus in two mole of compound 6 hydrogen atoms, 2 phosphorus atom and 8 oxygen atoms are present.
I'm pretty sure the formula is 2n(/\) 2
